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Vlad [161]
3 years ago
9

What is the simplified form of (-3x3y2) (5xy-1)

Mathematics
1 answer:
arlik [135]3 years ago
7 0
Simplify the expression
-15x4y3+3x3y2
Hope this helps! :)
~Zain
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Find the center and radius of (x-4)2 + (y+2)2 = 32
Trava [24]

Step-by-step explanation:

General equation of the circle with center (h,k) and radius r,

(x-h)²+(y-k)²=r²

Therefore, on comparison

center ( 4, -2)

radius r= 4√2

6 0
3 years ago
I guess u have to find the area
Nesterboy [21]
18
Because 6•3= 18
Hope this helped
7 0
3 years ago
Read 2 more answers
What is the quotient of -3/8 and -1/3 <br> O -1 1/8<br> O -1/8<br> O 1/8<br> O 1 1/8
Nat2105 [25]
The quotient of -3/8 and -1/3 is 1 1/8.
3 0
2 years ago
g Use this to find the equation of the tangent line to the parabola y = 2 x 2 − 7 x + 6 at the point ( 4 , 10 ) . The equation o
natali 33 [55]

Answer:

The tangent line to the given curve at the given point is y=9x-26.

Step-by-step explanation:

To find the slope of the tangent line we to compute the derivative of y=2x^2-7x+6 and then evaluate it for x=4.

(y=2x^2-7x+6)'          Differentiate the equation.

(y)'=(2x^2-7x+6)'       Differentiate both sides.

y'=(2x^2)'-(7x)'+(6)'    Sum/Difference rule applied: (f(x)\pmg(x))'=f'(x)\pm g'(x)

y'=2(x^2)'-7(x)'+(6)'  Constant multiple rule applied: (cf)'=c(f)'

y'2(2x)-7(1)+(6)'        Applied power rule: (x^n)'=nx^{n-1}

y'=4x-7+0               Simplifying and apply constant rule: (c)'=0

y'=4x-7                    Simplify.

Evaluate y' for x=4:

y'=4(4)-7

y'=16-7

y'=9 is the slope of the tangent line.

Point slope form of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on the line.

Insert 9 for m and (4,10) for (x_1,y_1):

y-10=9(x-4)

The intended form is y=mx+b which means we are going need to distribute and solve for y.

Distribute:

y-10=9x-36

Add 10 on both sides:

y=9x-26

The tangent line to the given curve at the given point is y=9x-26.

------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function f(x)=2x^2-7x+6 at x=4 (the slope of the tangent line at x=4):

\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}

\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}  We are given f(4)=10.

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

2x^2-7x-4=(x-4)(2x+1)

Let's check this with FOIL:

First: x(2x)=2x^2

Outer: x(1)=x

Inner: (-4)(2x)=-8x

Last: -4(1)=-4

---------------------------------Add!

2x^2-7x-4

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}

\lim_{x \rightarrow 4}(2x+1)

Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

6 0
3 years ago
5 Find each probability if you pick two marbles without replacing the first (G = green; R = red; Y = yellow).
Dennis_Churaev [7]

Answer:

Sorry but your question is incomplete!

it's impossible to answer this question if we don't know the <u>total number of outcomes</u>

<em>I'm referring to writing the question instead of OCR-ing it</em>

4 0
2 years ago
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