All categories

3 years ago

Help please I give you a cookie

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

3 0

K and j are adjacent

You might be interested in

What steps transform the graph of y=x^2 to y= -(x+3)^2+5

Lady bird [3.3K]

$\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)= A( Bx+ C)+ D
\\\\
~~~~y= A( Bx+ C)+ D
\\\\
f(x)= A\sqrt{ Bx+ C}+ D
\\\\
f(x)= A(\mathbb{R})^{ Bx+ C}+ D
\\\\
f(x)= A sin\left( B x+ C \right)+ D
\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\
\bullet \textit{ flips it upside-down if } A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if } B\textit{ is negative}$

$\bf ~~~~~~\textit{reflection over the y-axis}
\\\\
\bullet \textit{ horizontal shift by }\frac{ C}{ B}\\
~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by } D\\
~~~~~~if\ D\textit{ is negative, downwards}\\\\
~~~~~~if\ D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{ B}$

now, with that template in mind, let's check this one

$\bf y=x^2\implies y=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+0})^2\stackrel{D}{+0}
\\\\\\
y=-(x+3)^2+5\implies y=\stackrel{A}{-1}(\stackrel{B}{1}x\stackrel{C}{+3})^2\stackrel{D}{+5}$

A = -1, reflection over the x-axis.

B = 1, C = +3, C/B = +3/1 = +3, horizontal shift to the left of 3 units.

D = 5, vertical shift up of 5 units.

4 0

3 years ago

specific park is rectangular-shaped and has a 7-mile perimeter. The length is 4 times the width. What are the dimensions of the

denis23 [38]

This is an algabraic problem, so we would use variables:
Length=x
Width=y
The length is four times the width, so
x=4y
Since the equation for perimeter is P= 2(x+y), you would instead substitute 4y for x, and 7 for the perimeter.
7=2(4y+y)
Simplify.
7=2(5y)
7=10y
y=7/10
Since y is 7/10, you would substitute 7/10 into the equation x=4y.
x=4(7/10)
x=14/5
So, the dimensions are 7/10 x 14/5.
Hope this helps!

7 0

3 years ago

Put these in order of size smallest first. 0.1 30% 1/5

Murljashka [212]

0.1 < 0.2 < 0.3

Since 1/5 = 0.2 and 30% = 30/100 wich is 0.3

4 0

3 years ago

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

3 0

3 years ago

If a system of linear equations has no solution, then

Natali5045456 [20]

Answer:

If a system of linear equations has no solution,then it is said to be inconsistent.The graphs of the lines do not intersect,and therefore the graphs are parallel and there is no solution.

Step-by-step explanation:

If a system of linear equations has no solution,then it is said to be inconsistent.The graphs of the lines do not intersect,and therefore the graphs are parallel and there is no solution.

5 0

3 years ago

Read 2 more answers