Answer:
Step-by-step explanation:
KL = JK, so ΔJKL is an isocesles triangle, then m∠J = m∠L
KL is a tangent line, so ∠JKL = 90°,
so m∠J = 45°
Answer:
Put the green dot at the coordinates (-3, -4). Find -3 on the x-axis and go 4 down.
Step-by-step explanation:
Just move the blue dot five to the left, then five to the left again.
Answer:
Final answer is 
Step-by-step explanation:
We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).
So first we need to find the slope of given line.
rewirite x=6y-5 in y=mx+b form
x+5=6y

Compare given equation with y=mx+b
we get: m=1/6
We know that parallel equations has equal slope.
Then slope of required line m=1/6
Now plug the given point (5,-3) and slope m=1/6 into point slope formula:





Now we need to rewrite that equation in standard form. Ax+By=C.
6y=x-23
x-23=6y
x-6y=23
Hence final answer is 