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Verizon [17]
2 years ago
14

Can y’all help me I’ll give the brain thingy

Mathematics
1 answer:
VARVARA [1.3K]2 years ago
5 0

Answer:

di ku alam

Step-by-step explanation:

nakakalitu kasi yan sa iba nalang po

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Solve the given equation by completing the square.
klasskru [66]

Answer:

Step-by-step explanation:

x^2+8x=38\\\\x^2+8x-38=0\\\\\Delta=8^2+4*38=216=6^3\\\\x=\dfrac{-8-6\sqrt{6}  }{2} \ or\ x=\dfrac{-8+6\sqrt{6}  }{2}\\\\x=-4-3\sqrt{6} \ or\ x=-4+3\sqrt{6}\\\\a=-4\\b=3\\c=6\\

3 0
3 years ago
Solve this inequality : 5x+7x<36
Lera25 [3.4K]

Answer:

x < 3

Step-by-step explanation:

5x+7x<36

12x<36

Divide both sides by 12

x<3

7 0
3 years ago
Find the distance (8,-7) (-4,-2)
Vinil7 [7]

Distance = 13 units

Point A: (8, -7)

Point B: (-4, -2)

\sqrt{(8 + 4)^{2} + (-7 + 2)^{2} }

\sqrt{(12)^{2} + (-5)^{2} }

\sqrt{144 + 25 }

\sqrt{169}

13

7 0
3 years ago
Read 2 more answers
Add the following rational number7/-27 and 11/18
poizon [28]

Answer:

19/54

Step-by-step explanation:

- 7/27 + 11/18

LCM of the 27, 18 is 54

- 7/27 * (2/2) + 11/18 * (3/3)

- 14/54 + 33/54

33 - 14/54

19/54

please mark me brainlist

3 0
2 years ago
Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu
kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

f(x) =  {x}^{5}  -  {x}^{3}  + 6

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

f'(x) = 5 {x}^{4} - 3 {x}^{2}

At turning point f'(x)=0.

5 {x}^{4} - 3 {x}^{2}  = 0

This implies that,

{x}^{2} (5 {x}^{2}  - 3) = 0

{x}^{2}  = 0 \: or \: 5 {x}^{2}  - 3 = 0

x =  - \frac{ \sqrt{15} }{5}   \: or \: x = 0 \:  \: or \: x =\frac{ \sqrt{15} }{5}

We plug this values into the original function to obtain the y-values of the turning points

(   -  \frac{ \sqrt{15} }{5}  , \frac{1}{125} ( 6 \sqrt{15}  +750)) \:and \:  (0, - 6) \: and\: (   \frac{ \sqrt{15} }{5}  , \frac{1}{125} ( - 6 \sqrt{15}  +750))

We now use the second derivative test to determine the absolute maximum minimum on the interval [-1,1]

f''(x) = 20 {x}^{3}  - 6x

f''( -  \frac{ \sqrt{15} }{5} ) \:   <  \: 0

Hence

(   -  \frac{ \sqrt{15} }{5}  , \frac{1}{125} ( 6 \sqrt{15}  + 750))

is a maximum point.

f''( \frac{ \sqrt{15} }{5} ) \:    >  \: 0

Hence

(     \frac{ \sqrt{15} }{5}  , \frac{1}{125} (- 6 \sqrt{15}  + 750))

is a minimum point.

f''(0) \: =\: 0

Hence (0,-6) is a point of inflexion

4 0
3 years ago
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