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Verizon [17]
3 years ago
14

Can y’all help me I’ll give the brain thingy

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
5 0

Answer:

di ku alam

Step-by-step explanation:

nakakalitu kasi yan sa iba nalang po

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Solve the right triangle, AABC, for the missing sides and angle to
jolli1 [7]

Answer:

please see photo for detailed analysis.

8 0
2 years ago
Write an ordered pair corresponding to the point G.
Tasya [4]

Answer:

The ordered pair is (-4,2) this is the ordered pair because x=-4 and the y=2

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
20 + 17y = -6 + 15y<br><br> Can you help me find y?
MariettaO [177]
20 + 17y = -6 + 15y

First, regroup your terms.
20 + 17y = 15y - 6
Second, take away '15y' from each side.
20 + 17y - 15y = -6
Third, subtract '17y - 15y' to get '2y'.
20 + 2y = -6
Fourth, take away '20' from both sides.
2y = -6 - 20
Fifth, simplify '-6 - 20' to get '-26'.
2y = -26
Sixth, divide both sides by '2'.
y =  -\frac{26}{2}
Seventh, how many times goes 2 go into 26? 26 ÷ 2 = 13.
y = -13

Answer: y = -13

4 0
3 years ago
Math question #1 please show steps
-Dominant- [34]

Answer:

C

Step-by-step explanation:

An approximation of an integral is given by:

\displaystyle \int_a^bf(x)\, dx\approx \sum_{k=1}^nf(x_k)\Delta x\text{ where } \Delta x=\frac{b-a}{n}

First, find Δx. Our a = 2 and b = 8:

\displaystyle \Delta x=\frac{8-2}{n}=\frac{6}{n}

The left endpoint is modeled with:

x_k=a+\Delta x(k-1)

And the right endpoint is modeled with:

x_k=a+\Delta xk

Since we are using a Left Riemann Sum, we will use the first equation.

Our function is:

f(x)=\cos(x^2)

Therefore:

f(x_k)=\cos((a+\Delta x(k-1))^2)

By substitution:

\displaystyle f(x_k)=\cos((2+\frac{6}{n}(k-1))^2)

Putting it all together:

\displaystyle \int_2^8\cos(x^2)\, dx\approx \sum_{k=1}^{n}\Big(\cos((2+\frac{6}{n}(k-1))^2)\Big)\frac{6}{n}

Thus, our answer is C.

*Note: Not sure why they placed the exponent outside the cosine. Perhaps it was a typo. But C will most likely be the correct answer regardless.

5 0
3 years ago
Would 1/5 be greater than 1/3 but less than 2/3
makvit [3.9K]
1/5 = 3/15
1/3 = 5/15
2/3 = 10/15
So no :)

Reason why:
You want to find the common denominator between all three fractions, so all fractions are the same proportions. So in this case, if you multiply 5*3 you get 15, making it the common denominator. Then since you multiplied the 5 in 1/5 by 3 to get 15, and you have to multiply the 3 in 1/3 and 2/3 by 5 to get 15, then you multiply the numerator by the same number.

Sorry I am terrible at explaining things. Hope this helped though!
7 0
3 years ago
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