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OleMash [197]
3 years ago
8

does the bowling ball have more potential energy or kinetic energy as it half way through its fall?why

Mathematics
1 answer:
lesantik [10]3 years ago
5 0

Answer:

I think it is ikinetic because it gains speed as it gets closer to the ground.

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Task: Nonpermissible Values for Rational Expressions [30 points] Write a rational expression that has the nonpermissible values
igor_vitrenko [27]

Answer:

A rational expression that has the nonpermissible values x = 0 and x = 17 is f(x) = \frac{4}{x\cdot (x-17)}.

Step-by-step explanation:

A rational expression has a nonpermissible value when for a given value of x, the denominator is equal to zero. In addition, we assume that both numerator and denominator are represented by polynomials, such that:

f(x) = \frac{p(x)}{q(x)} (1)

Then, the factorized form of q(x) must be:

q(x) = x\cdot (x-17) (2)

If we know that p(x) = 4, then the rational expression is:

f(x) = \frac{4}{x\cdot (x-17)} (3)

A rational expression that has the nonpermissible values x = 0 and x = 17 is f(x) = \frac{4}{x\cdot (x-17)}.

8 0
2 years ago
Which of the pairs of events below is mutually exclusive?
Nady [450]

Answer:

Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards.

Step-by-step explanation:

Given four pair of events:

1. Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards

2. Drawing a 2 and drawing a 4 with replacement from a standard deck of cards

3. Drawing a heart and then drawing a spade without replacement from a standard deck of cards

4. Drawing a jack and then drawing a 7 without replacement from a standard deck of cards

To find:

Which of the pairs is mutually exclusive?

Solution:

First of all, let us have a look at the definition of mutually exclusive events.

Mutually exclusive events do not have any case in common.

In other words, two events are known as mutually exclusive when both the events can not occur at the same time.

Now, let us have a look at the given options one by one:

1. Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards.

We know that there is only one ace of spades in a standard deck.

Therefore, the two events can not occur one after the other, so these are mutually exclusive events.

2. Drawing a 2 and drawing a 4 with replacement from a standard deck of cards.

The two events can occur one after the other, so these are not mutually exclusive.

3. Drawing a heart and then drawing a spade without replacement from a standard deck of cards.

Separate cards are drawn one after the other, so not mutually exclusive.

4. Drawing a jack and then drawing a 7 without replacement from a standard deck of cards.

Separate cards are drawn one after the other, so not mutually exclusive.

3 0
2 years ago
Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the
motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point A(-2,3), we get;

(-2,3)\rightarrow (-2,-3)

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point B(0,3), we get;

(0,3)\rightarrow (0,-3)

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point C(-1,-1), we get;

(-1,-1)\rightarrow (-1,1)

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0
3 years ago
(2x^2+x+3)/(x-2)with remainder
Leni [432]

Answer:

2x+5 r. 13

Step-by-step explanation:

So using long division, you can solve for the quotient and the remainder.

Please look at the attached for the solution.

Step 1: need to make sure that you right the terms in descending order. (If there are missing terms in between, you need to fill them out with a zero so you won't have a problem with spacing)

Step 2: Divide the highest term in the dividend, by the highest term in the divisor.

Step 3: Multiply your result with the divisor and and write it below the dividend, aligning it with its matched term.

Step 4: Subtract and bring down the next term.

Repeat the steps until you cannot divide any further. If you have left-overs that is your remained.

3 0
2 years ago
The inverse of this equation
In-s [12.5K]

Answer:

{f}^{ - 1}(x)  =  \frac{x + 11}{ - 5}

Step-by-step explanation:

f(x) =  - 5x - 11 \\  - 5x - 11 =x \\  - 5x = x + 11 \\  {f}^{ - 1}(x)  =  \frac{x + 11}{ - 5}

7 0
3 years ago
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