Answer:
9pr = 2q^2
Step-by-step explanation:
28.
px^2 + qx + r = 0
If one root is A then the other root is 2A
We have A + 2A = -q/p and A*2A = r/p
So 3A = -q/p so A = -q/3p and A^2 = r/2p so A = √ (r / 2p)
Equating these 2 equations:-
-q/3p = √(r / 2p)
q^2 / 9p^2 = r / 2p
9p^2r = 2pq^2
9pr = 2q^2 (answer)
Answer:
187
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
(3 + 2)² × 7 - 13 + 5²
<u>Step 2: Evaluate</u>
- (Parenthesis) Add: 5² × 7 - 13 + 5²
- Exponents: 25 × 7 - 13 + 25
- Multiply: 175 - 13 + 25
- Subtract: 162 + 25
- Add: 187
Answer:
-1
Step-by-step explanation:
-5-15+4+15
=-20+19
=-1
Answer:
yes
Step-by-step explanation: