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3 years ago

7

In a fraction with a denominator of 15, which value could the numerator be to produce a repeating decimal? A) 9 B) 11 C) 12 D) 1

5

1 answer:

Damm [24]3 years ago

4 0

Out of the following choices, the value that could be the numerator to produce a repeating decimal is 12. The correct answer will be C .

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Need help please thanks

tekilochka [14]

I'm guessing d b are equal and a and c are equal or I don't think we would be able to solve so going on that
if angle d is 57 angle b must also be 57
A parallelegram has angles that add up to 360
So 360= 57+57+2c
Solve
360=114+2c
-114 both sides
246=2c
÷2 both sides
123=c

6 0

3 years ago

- 7th Grade Work -<br><br> I rlly need help ; - ;

Tanya [424]

Answer:

The length would be 1.5x + 5.

Step-by-step explanation:

So first with this, note that 2 length + 2 height gives the perimeter of the rectangle.

Given this:

2(1/2x + 4) + 2(?) = 4x+18

x+8 + 2(?) = 4x+18

2(?) = 3x+10

? = 1.5x+5

1.5x + 5 = 1.5x + 5

The length would be 1.5x + 5.

To double check, by plugging in 1.5x + 5 back into the equation for the perimeter, you will get the same perimeter:

2(1.5x + 5) + 2(1/2x+4) = P

3x+10 + x+8 = P

4x + 18 = P

8 0

3 years ago

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago

Bill is 2 years older than his brother Will. If the product of their ages is one less than five times the sum of their ages, how

Advocard [28]

Answer:

Will's age = 9 years

Bill's age = 11years

Step-by-step explanation:

Let will age = x

Bill = x +2 since he is 2 years older

x(x+2) = 5( x +x+2) - 1

Opening brackets

x² + 2x = 5(2x + 2) - 1

x² + 2x = 10x + 10 - 1

x² + 2x = 10x + 9

Collect like terms

x² + 2x - 10x - 9 = 0

x² - 8x - 9 = 0

Solve quadratically using factorisation method by finding two factors of +9 that can add up to give -8, the coefficient of x.

The factors are -9 and +1

x² + x - 9x - 9 = 0

x(x + 1) -9( x +1)

x+1) (x -9) =0

x + 1 = 0 or x -9 =0

x = -1 or 9

Age can not be negative

Therefore,

Will's age = 9 years

Bill's age = x+2 = 9+2 = 11years

I hope this was helpful, please rate as brainliest

6 0

3 years ago

WHOEVER ANSWERS 1ST AND HAS CORRECT ANSWER WILL GET MARKED AS BRAINILIEST

Dovator [93]

It is C. Associative property of multiplication

3 0

3 years ago