We need the following to be true
a+2b = -a
a+4 = 2a - 3b
Let's look at the first equation.
a + 2b = -a
Subtract both sides by a
2b = -2a
b = -a
Substitute b= -a into the second equation
a+4 = 2a + 3a
a + 4 = 5a
4a = 4
a = 1
Just take the negative of that and you get the value of b.
b = -1
Your solution is a=1 and b = -1.
Have an awesome day! :)
CF = CD + DF (since D is simply a point on the line, and C to that point added onto F to that point is CF), so 4y-9+2y-7=14. Adding it up, we get 6y-16=14 and adding by 16 we get 30=6y. Dividing both sides by 6, we get y=5. Plugging that into DF, we get 10-7=DF=3
Represent the number of days by x. With this representation, the variable cost of the rental is 31.67x. The total cost is the sum of the fixed and variable costs. This value should not be more than $500. The equation below shows the relationship.
130 + 31.67x ≤ 500
Solving for x gives x ≤ 11.68
Thus, the maximum number of days to rent the car is only 11 days.
If you are doing a literal equation all you have to do is isolate the h.
First get rid of the fraction by multiplying both sides by 2.
2a=bh
Then divide both sides by b.
2a/b=h
Hope this helps!
