In slope-intercept form, what is the equation of the line passing through the points (-4.26) and (6-4)?

Mathematics

1 answer:

Harlamova29_29 [7]4 years ago

5 0

Answer:

y=-3x+14

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-4-26)/(6-(-4))

m=-30/(6+4)

m=-30/10

m=-3

y-y1=m(x-x1)

y-26=-3(x-(-4))

y-26=-3(x+4)

y=-3x-12+26

y=-3x+14

You might be interested in

If P(event A) = 0.25, what is P(not event A)?

xz_007 [3.2K]

Answer:

0.75

Step-by-step explanation:

The probability of P(not event a) is equal to 1-p(event A)

3 0

3 years ago

A $104.000 selling price with $24.000 down at 81/2% for 25 years results in monthly payments of

Vinil7 [7]

The monthly payment would be $289.33

$104,000 - $24,000 = $80,000
$80,000 x %8.5 interest = $6,800
$80,000 + $6,800 = $86,800 (total being paid back)
12 (total of months in a year) x 25 (number of years) = 300
Divide $86,800 by 300 and your monthly payment is $289.33

4 0

3 years ago

Read 2 more answers

Create the equation of a line that perpendicular to 2y=14+2/3x and passes through the point (-2,8).

riadik2000 [5.3K]

Answer:

y = - 3x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 2y = 14 + $\frac{2}{3}$ x into this form