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svetoff [14.1K]
3 years ago
9

To find 1% of a number, move the decimal

Mathematics
2 answers:
dangina [55]3 years ago
7 0

To find 1% of a number, move the decimal 2 places to the left.

May I have brainliest please? :)

Arte-miy333 [17]3 years ago
6 0

Answer:

2 places to the left

Step-by-step explanatiS

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If the marginal propensity to consume is 0.9, what is the maximum amount that the equilibrium gross domestic product could chang
Katen [24]

Answer: There is change of $0.9 billion in government expenditures.

Step-by-step explanation:

Since we know that

Marginal propensity to consume tells that the rate at which there is change in consumption due to change in income.

According to our situation, MPC is the change in amount of gross domestic product due to change in government expenditure.

So, it becomes,

MPC=\dfrac{\text{Change in gross domestic product}}{\text{Change in government expenditure}}\\\\0.9=\dfrac{x}{1}\\\\x=0.9

Hence, there is change of $0.9 billion in government expenditures.

7 0
3 years ago
“Express each of the following numbers using scientific notation “
avanturin [10]

11. 1.97 * 10^-6

12. 3.5 * 10^-3

13. 2.28 * 10^13

14. 5.302 * 10^-3

15. 1.64 * 10^1

16. 9.85 * 10^-1

Can you see the pattern?

Try the rest yourself

5 0
3 years ago
A cone-shaped building has a height of 11.4 meters and a base with a diameter of 12 meters. The building will be filled with roa
Lyrx [107]
We know, Volume of a Cone = πr² h/3
v = 3.14 * (6)² * 11.4/3
v = 3.14 * 36 * 3.8
v = 429.552

Now, for 1 m³, it costs = $20
So, for 429.552 m³, it will be: 20 * 429.552 = 8591

In short, Your Answer would be $8591

Hope this helps!
3 0
4 years ago
Read 2 more answers
Solve the two-step equation.− 23 x – 214 = 274x =
Pachacha [2.7K]
U have to divide the numbers with the variables and then you'll get knocked down to the division and u have your answers and it is possible to have 1 or 2 answers v

4 0
3 years ago
Read 2 more answers
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
2 years ago
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