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Harman [31]
3 years ago
10

Quadrilateral ABCD is the result of a reflection of quadrilateral EFGH over the line. Which line segment in the image correspond

s to BC¯¯¯¯¯ in the pre-image? Picture attached answer choices are in picture

Mathematics
2 answers:
solong [7]3 years ago
8 0
The answer is b). GH good luck
Butoxors [25]3 years ago
8 0

Answer:

D

Step-by-step explanation: So, this is a reflection of the quadrilateral ABCD. Which means, the angles in the quadrilateral are going to be the same, but in a different position. (on the oposite side of the axis.)  Which means, if you line them up, you could easily see.. The answer. D is the correct answer.


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I NEED PLEASE HELP ASAP
azamat

Answer:

Step-by-step explanation:

the lat answer for the first picture correct just plug it in the hihger number for x and then try a larger number y decreases. The same answer for the second one 2

7 0
3 years ago
The figure shows the construction steps to bisect an angle. The steps are in an incorrect order. What is the correct order of th
klemol [59]

Answer:

The correct order of the steps is CEABD ⇒ B

Step-by-step explanation:

Let us arrange the figures

To construct a bisector of an angle

First: Draw angle AOB

First step is figure C

Second: Place the pin of the compass on point O and draw an arc intersects the two sides of the angle OA and OB at points D and E

Second step is figure E

Third: Place the compass on point D and draw an arc in the interior of the angle

Third step is figure A

Fourth: without change the open of the compass place its pin on point E and draw an arc which intersects the arc drawn from point D at point C

Fourth step is figure B

Fifth: Draw a line from point A to point C, this line AC is the bisector of angle AOB

Fifth step is figure D

The correct order of the steps is CEABD

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3 years ago
Please help me with question number 2
Mice21 [21]

Answer:

2. The area of the side walk is approximately 217 m²

3. The distance away from the sprinkler the water can spread is approximately 11 feet

4. The area of the rug is 49.6

Step-by-step explanation:

2. The dimensions of the flower bed and the sidewalks are;

The diameter of the flower bed = 20 meters

The width of the circular side walk, x = 3 meters

Therefore, the diameter of the outer edge of the side walk, D, is given as follows

D = d + 2·x (The width of the side walk is applied to both side of the circular diameter)

∴ D  = 20 + 2×3 = 26

The area of the side walk = The area of the sidewalk and the side walk = The area of the flower bed

∴ The area of the side walk, A = π·D²/4 - π·d²/4

∴ A = 3.14 × 26²/4 - 3.14 × 20²/4 = 216.66

By rounding to the nearest whole number, the area of the side walk, A ≈ 217 m²

3. Given that the area formed by the circular pattern, A = 379.94 ft.², we have;

Area of a circle = π·r²

∴ Where 'r' represents how far it can spread, we have;

π·r² = 379.94

r = √(379.94 ft.²/π) ≈ 10.997211 ft.

Therefore, the distance away from the sprinkler the water can spread, r ≈ 11 feet

4. The circumference of the rug = 24.8 meters

The circumference of a circle, C = 2·π·r

Where;

r = The radius of the circle

π = 3.1

∴ For the rug of radius 'r', C = 2·π·r = 24.8

r = 24.8/(2·π) = 12.4/π = 12.4/3.1 = 4

The area = π·r²

∴ The area of the rug = 3.1 × 4² = 49.6.

8 0
2 years ago
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Answer:

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A student earns $9 for 1 h and $36 for 4 h
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I do not the question. Please explain

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