Quadrilateral ABCD is the result of a reflection of quadrilateral EFGH over the line. Which line segment in the image correspond
s to BC¯¯¯¯¯ in the pre-image? Picture attached answer choices are in picture
2 answers:
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Answer:
115.48
Step-by-step explanation:
This shape can be split into two distinct shapes
Two halves of a semi circle, and a rectangle in between
Circle:
Putting both halves of the semi circle together will give you a full circle. The diameter of the circle is given (7m).
The area of a circle is A = π
The radius, r, is half of the diameter, so 7 / 2 = 3.5m
A = π
A = π *
A = 38.38
Rectangle:
The area of a rectangle is A = h b
The height, h, is known at 7m
The base, b, can be found by removing the length from the dot to the end of the semi circles. This length is the radius of the semi circles, 3.5m
Removing the radius from the total length given
18 - 3.5 - 3.5 = 11m
The base is 11m
A = h b
A = 7 * 11 = 77
Total Area = Circle area + Rectangle area
Total Area = 38.38 + 77 = 115.48
Answers:
f(-3) = -1
f(-1) = 2
f(3) = 5
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Explanations:
Draw a vertical line through -3 on the x axis. Make sure this vertical line crosses the orange graph. Mark this point of intersection and then draw a horizontal line from this point to the y axis. You should find that it touches -1 on the y axis. Check out the attached image to see this process in action.
Those steps basically say that x = -3 leads to y = -1. Since y = f(x), this means f(-3) = -1
Through similar steps, you should find that f(-1) = 2 and f(3) = 5
Note that the open hole/circle does not count. So if you land on an open hole, just keep going until you hit a closed circle on the other piece of the graph.
