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ycow [4]
3 years ago
11

As the frequency of electromagnetic waves increases, what happens to the wavelength?

Chemistry
2 answers:
Mnenie [13.5K]3 years ago
7 0

Answer:

It increases.

When the frequency of electromagnetic waves increases, the wavelengths also increase because the frequency sends power to the wavelengths.

tiny-mole [99]3 years ago
6 0

Answer:

it increases

Explanation:

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A gas system contains 2.00 moles of O2 and CO2 gas, has an initial temperature of 25.0 oC and is under 1.00 atm of pressure. If
Ainat [17]

Answer:

V_2=52.2L

Explanation:

Hello there!

In this case, by bearing to to mind the given conditions, it is firstly possible to determine the initial volume of the closed system via the ideal gas equation:

PV=nRT\\\\V=\frac{2.00mol*0.08206\frac{atm*L}{mol*K}*298.15K}{1.00 atm} \\\\V=48.9L

Which is V1 in the Charles' law:

\frac{T_2}{V_2} =\frac{T_1}{V_1}

And of course, T1 is 298.15 (25+273.15). Therefore, by solving for V2 as the final volume, we obtain:

V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{48.9L*(45+273.15)K}{(25+273.15)K}  \\\\V_2=52.2L

Best regards!

8 0
3 years ago
If earth is 1.50 x 108 km from the sun, what is the distance in tm?
ycow [4]
THE DISTANCE IN TM SHOULD BE EQUAL TO  162 KM

5 0
3 years ago
Please help me with this friends.​
Radda [10]
Where is the picture to this?
3 0
3 years ago
What is a bond called that shares electrons between two neutral atoms?
Andre45 [30]

Answer:

Probably covalent bonds

4 0
3 years ago
Read 2 more answers
B) How many kilojoules of heat will be released by the combustion of 22.52 g of this liquid at
snow_tiger [21]

Answer:

Explanation:

You realize that C2H5OH releases -1277.3kJ/mol. We need to convert this to the amount based on the question. We that 22.52g of C2H5OH = 0.48884 mol.

This means that it will release (-1277.3)(0.48884) = 624.40 KJ of heat will be released. Note the negative sign is not necessary here (I think) because it says how much is released and not the change in heat of the system so it should be positive.

3 0
2 years ago
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