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ycow [4]
2 years ago
11

As the frequency of electromagnetic waves increases, what happens to the wavelength?

Chemistry
2 answers:
Mnenie [13.5K]2 years ago
7 0

Answer:

It increases.

When the frequency of electromagnetic waves increases, the wavelengths also increase because the frequency sends power to the wavelengths.

tiny-mole [99]2 years ago
6 0

Answer:

it increases

Explanation:

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Answer:

to find out how somethings work

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A family takes a summer vacation to Florida. They drive for 8 hours before stopping at a hotel for the night. They
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Average speed of the trip = 52 km/hr

<h3>Further explanation  </h3>

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\tt S(speed)=\dfrac{D}{T}

Total distance travelled : 1560 km

Total time : 8 hr + 12 hr + 10 hr = 30 hr

\tt avg.speed=\dfrac{tot~D}{tot~T}\\\\avg.speed=\dfrac{1560}{30}\\\\avg.speed=52~km/hr

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Compared with halogens, the alkali metals in the same period has
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Alkali metals have the lowest electronegativities, while halogens have the highest.
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For the equilibrium
Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

H_2S=0.596M

H_2=0.004 M

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Explanation:

We are given that  for the equilibrium

2H_2S\rightleftharpoons 2H_2(g)+S_2(g)

k_c=9.0\times 10^{-8}

Temperature, T=700^{\circ}C

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H_2=0.30 M

S_2=0.150 M

We have to find the equilibrium concentration of gases.

After certain time

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Concentration of

H_2S=0.30+2x

H_2=0.30-2x

S_2=0.150-x

At equilibrium

Equilibrium constant

K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Substitute the values

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

By solving we get

x\approx 0.148

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H_2S=0.30+2(0.148)=0.596M

H_2=0.30-2(0.148)=0.004 M

S_2=0.150-0.148=0.002 M

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A sample of ideal gas is in a sealed container. The pressure of the gas is 505torr, and the temperature is 43 degree celsius. If
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Use PV=nRT to find V assuming n is one and R= 8.31 then use the answer to find P2
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