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kvasek [131]
3 years ago
15

10.7g of C2H2 --> g CO2

Chemistry
1 answer:
kicyunya [14]3 years ago
5 0

Answer:

http://www.khalidshadid.com/uploads/3/9/2/0/3920808/raymond_chang-chemistry_10th_edition.pdf

Explanation:

http://www.khalidshadid.com/uploads/3/9/2/0/3920808/raymond_chang-chemistry_10th_edition.pdf

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9.27 mol of oxygen is equal to______molecules of oxygen <br> Please help I need it
bixtya [17]
<h3>Answer:</h3>

5.58 × 10²⁴ molecules O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

9.27 mol O₂ (Oxygen)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                             \displaystyle 9.27 \ mol \ O_2(\frac{6.022 \cdot 10^{23} \ molecules \ O_2}{1  \ mol \ O_2})
  2. Multiply/Divide:               \displaystyle 5.58239 \cdot 10^{24} \ molecules \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules. We are given 3 sig figs.</em>

5.58239 × 10²⁴ molecules O₂ ≈ 5.58 × 10²⁴ molecules O₂

8 0
3 years ago
Dalam ruang 1 liter, gas metana (ch4) direaksikan dengan 6 mol uap air sesuai reaksi:ch4(
kakasveta [241]

In the space of 1 liter, methane gas (ch4) is reacted with 6 moles of water vapor according to the reaction: if at equilibrium state is obtained 4 moles of hydrogen gas, how many moles of methane gas is needed for the equilibrium reaction?

the reaction is

CH4(g)  + 2H2O(g)  ----> CO2(g)   + 4H2 (g)

Kc = 16 / 3

Kc = [CO2] [H2]^4 / [CH4] [H2O]^2

given :

equilibrium concentration

[H2] = 4 moles

so equilibrium concentration of CO2 must be 1 mole

equilibrium concentration of H2O = 6 - 2 = 4

putting values

16 /3 =  [1] [4]^4 / [CH4] [4]^2

[CH4] = 0.333 moles

so moles of CH4 required = 1.33 moles

5 0
3 years ago
In an exothermic reaction, the enthalpy change is negative. Which of the following is also true for an exothermic reaction?
Drupady [299]
A. The products have a lower potential energy than the reactants.
5 0
3 years ago
A neutron has a mass A. that is less than the mass of an electron. B. that is about equal to the mass of an electron. C. that is
soldi70 [24.7K]

Answer:

Option C:- that is equal to mass of an proton.

Explanation:

Protons and neutrons have approximately the same mass, about 1.67 × 10-24 grams, which scientists define as one atomic mass unit (amu) or one Dalton. While electron has mass of 9.31 ×10⁻¹⁹.

6 0
3 years ago
In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce ga
Reptile [31]

Answer:

The rate at which ammonia is being produced is 0.41 kg/sec.

Explanation:

N_2+3H_2\rightarrow 2NH_3 Haber reaction

Volume of dinitrogen consumed in a second = 505 L

Temperature at which reaction is carried out,T= 172°C = 445.15 K

Pressure at which reaction is carried out, P = 0.88 atm

Let the moles of dinitrogen be n.

Using an Ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.88 atm\times 505 L}{0.0821 atm l/mol K\times 445.15 K}=12.1597 mol

According to reaction , 1 mol of ditnitrogen gas produces 2 moles of ammonia.

Then 12.1597 mol of dinitrogen will produce :

\frac{2}{1}\times 12.1597 mol=24.3194 mol of ammonia

Mass of 24.3194 moles of ammonia =24.3194 mol × 17 g/mol

=413.43 g=0.41343 kg ≈ 0.41 kg

505 L of dinitrogen are consumed in 1 second to produce 0.41 kg of ammonia in 1 second. So the rate at which ammonia is being produced is 0.41 kg/sec.

6 0
3 years ago
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