What equals 16 in multiplication

Define the domain of the following

devlian [24]

The domain of the function or relation on the graph is { -2, -1, 0, 2 and 5}

<h3>What is the domain of a function?</h3>

The domain of the function is the set of input values of the graph

<h3>How to determine the domain of the function?</h3>

The function is represented by the set of relation or ordered pairs on the graph

The graph is given as an attachment

The ordered pairs in the relation on the graph are:

(x, y) = (-2, -3), (-1, -1), (0, 3), (2, 1) and (5, 2)

Remove the y values in the above domain

x = -2, -1, 0, 2 and 5

The x values represent the domain of the function

And the domain of the function is the set of input values of the graph

Hence, the domain of the function or relation on the graph is { -2, -1, 0, 2 and 5}

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7 0

2 years ago

express the limit as a definite integral on the given interval. lim n → [infinity] n ∑ i = 1 cos x i x i δ x , [ 2 π , 4 π ]

Lemur [1.5K]

The limit as a definite integral on the interval $\lim _{n \rightarrow \infty} \sum_{i=1}^n \frac{\cos x_i}{x_i} \Delta x$ on [2π , 4π] is $\int_{2\pi}^{4 \pi} \frac{\cos x}{x} d x$$ .

<h3>What is meant by definite integral?</h3>

A definite integral uses infinitesimal slivers or stripes of the region to calculate the area beneath a function. Integrals can be used to represent a region's (signed) area, the cumulative value of a function changing over time, or the amount of a substance given its density.

Definite integral, a term used in mathematics. is the region in the xy plane defined by the graph of f, the x-axis, and the lines x = a and x = b, where the area above the x-axis adds to the total and the area below the x-axis subtracts from the total.

If an antiderivative F exists for the interval [a, b], the definite integral of the function is the difference of the values at points a and b. The definite integral of any function can also be expressed as the limit of a sum.

Let the equation be

$\int_a^b f(x) d x=\lim _{n \rightarrow \infty} \sum_{i=1}^n f\left(x_i\right) \Delta x$

substitute the values in the above equation, we get

= $\lim _{n \rightarrow \infty} \sum_{i=1}^n \frac{\cos x_i}{x_i} \Delta x$ on [2π, 4π],

simplifying the above equation

$\int_{2\pi}^{4 \pi} \frac{\cos x}{x} d x$$

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8 0

1 year ago

FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli

____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0

1 year ago

Thomas is opening a savings account. Which integer represents his possible balance after making a deposit?

Ray Of Light [21]

10 is the answer …………..

8 0

3 years ago

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Carlos had 7¾ cups of cheese. After making 5 pizzas, he now only has 2 cups of cheese. How much cheese did Carlos use?

Musya8 [376]

Answer:

5 3/4 cups of cheese used for the pizza

Step-by-step explanation:

7 3/4 = 31/4 cups cheese to start

Two cups of cheese remaining. 2 = 8/4 cups

31/4 cups - 8/4 cups = 23/4 cups used for the pizza.

23/4 = 5 3/4 cups of cheese used for the pizza

4 0

2 years ago