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nataly862011 [7]
2 years ago
15

Please help me. look at the picture.

Mathematics
1 answer:
Butoxors [25]2 years ago
6 0
It’s 0.775x +2.5 =correct
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I really need help pls. Its about 3d shapes
Svet_ta [14]

The image is blurry

Step-by-step explanation:

3 0
3 years ago
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From 1960 to 2010, a certain money stock measure was growing at the rate of approximately 43e(1/2)x billion dollars per decade,
natulia [17]

Answer:

1222 billion dollars.

Step-by-step explanation:

To find the total increase from 1960 to 2010, we need to find the growth of each decade and sum them all:

In the period 1960-1970, we have x = 1, and the growth is:

y(1) = 43e(1/2) = 70.895

In the period 1970-1980, we have x = 2, and the growth is:

y(2) = 43e(2/2) = 116.8861

The growth in the following 3 periods are:

y(3) = 43e(3/2) =192.7126

y(4) = 43e(4/2) = 317.7294

y(5) = 43e(5/2) =523.8472

So the total growth in the period 1960 - 2010 is:

Total = y(1) + y(2) + y(3) + y(4) + y(5)

Total = 70.895 + 116.8861+192.726+317.7294+523.8472

Total = 1222.08\ billion\ dollars

Rounding to the nearest billion dollars, we have a total of 1222 billion dollars.

6 0
3 years ago
Help me I’m not sure the answe
DiKsa [7]

Answer:

i believe it would be the last option.

Step-by-step explanation:

3 0
3 years ago
The mean of a data set is 16. What is the absolute deviation of a data point at 19?
S_A_V [24]

Answer:

i need a set of numbers to do this

Step-by-step explanation:

4 0
3 years ago
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Which table shows a proportional relationship between x and y ?
insens350 [35]

Answer:

Table C

Step-by-step explanation:

Given

Table A to D

Required

Which shows a proportional relationship

To do this, we make use of:

k = \frac{y}{x}

Where k is the constant of proportionality.

In table (A)

x = 2, y = 4

k = \frac{y}{x}

k = \frac{4}{2}

k = 2

x = 4, y = 9

k = \frac{y}{x}

k = \frac{9}{4}

k = 2.25

Both values of k are different. Hence, no proportional relationship

In table (B)

x = 3, y = 4

k = \frac{y}{x}

k = \frac{4}{3}

k = 1.33

x = 9, y = 16

k = \frac{y}{x}

k = \frac{16}{9}

k = 1.78

Both values of k are different. Hence, no proportional relationship

In table (C):

x = 4, y = 12

k = \frac{y}{x}

k = \frac{12}{4}

k = 3

x = 5, y = 15

k = \frac{y}{x}

k = \frac{15}{5}

k = 3

x = 6, y = 18

k = \frac{y}{x}

k = \frac{18}{6}

k = 3

This shows a proportional relationship because all values of k are the same for this table

7 0
3 years ago
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