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Delicious77 [7]
3 years ago
10

Sammy's Sandwich Shop has a mean delivery time of 25 minutes with a standard deviation of 2 minutes. Determine the z-score for t

he number of sandwiches delivered in less than 23 minutes. −1 1 11.5 12.5
Mathematics
1 answer:
Jlenok [28]3 years ago
7 0

Answer:the z score is - 1

Step-by-step explanation:

Assuming a normal distribution for the delivery time of sandwiches by Sammy's Sandwich Shop. We would apply the formula for normal distribution which is expressed as

z = (x - u)/s

Where

x = delivery times

u = mean delivery time

s = standard deviation

From the information given,

u = 25 minutes

s = 2 minutes

We want to determine the z-score for the number of sandwiches delivered in less than 23 minutes. It becomes

z = (23 - 25)/2 = - 1

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-18= 5-(6k - 19) i have the answer but i need help on how to get the answer 7?
insens350 [35]

Answer:

k = 7

Step-by-step explanation:

Step 1: Write equation

-18 = 5 - (6k - 19)

Step 2: Solve for <em>k</em>

<u>Distribute negative:</u> -18 = 5 - 6k + 19

<u>Combine like terms:</u> -18 = -6k + 24

<u>Subtract 24 on both sides:</u> -42 = -6k

<u>Divide both sides by -6:</u> k = 7

Step 3: Check

<em>Plug in k to verify it's a solution.</em>

-18 = 5 - (6(7) - 19)

-18 = 5 - (42 - 19)

-18 = 5 - 23

-18 = -18

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3 years ago
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3 years ago
Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?
vichka [17]

Answer:

The expression -1+14i represents  the number 2i^4-5i^3+3i^2+\sqrt{-81} rewritten in a+bi form.

Step-by-step explanation:

The value of i is i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4} in term of i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}

Substituting the value,

i^{4}=\left(-1\right)\times \left(-1\right)

Product of two negative numbers is always positive.

\therefore i^{4}=1

Now i^{3} in term of i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i

Substituting the value,

i^{3}=\left(-1\right)\times i

Product of one negative  and one positive numbers is always negative.

\therefore i^{3}=-i

Now \sqrt{-81} can be written as follows,

\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}

Applying radical multiplication rule,

\sqrt{ab}={\sqrt{a}}\sqrt{b}

\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}

Now, \sqrt{\left(81\right)=9 and \sqrt{-1}}=i

\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i

Now substituting the above values in given expression,

2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i

Simplifying,

2+5i-3+9i

Collecting similar terms,

2-3+5i+9i

Combining similar terms,

-1+14i

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0
3 years ago
Relationship B has a lesser rate than Relationship A. The graph represents Relationship A.
Zinaida [17]
Given that Relationship B has a lesser rate than Relationship A and that the graph representing Relationship A is a f<span><span>irst-quadrant graph showing a ray from the origin through the points (2, 3) and (4, 6) where the horizontal axis label is Time in weeks and the vertical axis label is Plant growth in inches.</span>

The rate of relationship A is given by the slope of the graph as follows:

slope= \frac{6-3}{4-2} = \frac{3}{2} =1.5

To obtain which table could represent Relationship B, we check the slopes of the tables and see which has a lesser slope.

For table A.
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slope= \frac{4.5-2.25}{6-3} = \frac{2.25}{3} =0.75

For table B.
Time (weeks) 3 6 8 10
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</span><span><span>slope= \frac{9.6-4.8}{6-3} = \frac{4.8}{3} =1.6

</span> For tabe C.
Time (weeks) 3 4 6 9
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</span><span>slope= \frac{7.2-5.4}{4-3} = \frac{1.8}{1} =1.8

For table D.
Time (weeks) 3 4 6 9
Plant growth (in.) 6.3 8.4 12.6 18.9</span>

<span>slope= \frac{8.4-6.3}{4-3} = \frac{2.1}{1} =2.1</span>

Therefore, the table that could represent Relationship B is table A.
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3 years ago
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Art [367]

Answer:

12.4 is the answer

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3 years ago
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