1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
patriot [66]
3 years ago
10

A specific brand of gourmet chocolate candy contains 7.00 gg of dietary fat in each 22.7-gg piece. How many kilograms of dietary

fat are in a box containing 4.00 lblb of candy? Express your answer numerically in kilograms.
Mathematics
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer:

635599482kg

Step-by-step explanation:

A gourmet chocolate candy has 7.00 gg of dietary fat in each 22.7-gg piece

for the 22.7 piece , the gg is 7 x 22.7  = 158.9gg in total

1gg = 2204622.6218488 lbs

158.9gg in total  = 158.9 x 2204622.6218488 = 350314534.612

for the box of 4.00 lblb of candy

it is 350314534.612 x 4 = 1401258138.45lb

since our answer is needed in kilograms we convert 1401258138.45lb to kilograms

1lb = 0.453592kg

1401258138.45lb =  1401258138.45lb x 0.453592kg = 635599481.513 ≈ 635599482kg

You might be interested in
Can u guys help i need to make this longer lol
Marizza181 [45]
I don’t under stand the question. What do you want me to answer
5 0
3 years ago
english has 26 different letters. how many consecutive words have to be selected in a book to have at least 5 that start with th
Valentin [98]

The words need not be English language words  142506

What is permutation and combination?

A set of elements can be divided into subsets in two different ways: combination and permutation.

                          The components of the subset may be arranged in any order when combined. The components of the subset are listed in a permutation in a certain order.

If the word has 5 different letters  then it is just 26-choose-5 or (26/5).

If the word has 4 different letters  then it is just 26-choose-4 or (26/4)

have 4 options to choose which letter to duplicate twice.

This gives =  4*(26/4)

If the word has 3 different letters  then it is just 26-choose-3 or (26/3).

you duplicate one of the three letters 3 times - 3 options for that, or you choose 2 letters and duplicate each one twice - again 3 options. In total this gives  = 6*(26/3).

If the word has 2 different letters  then it is just 26-choose-2 or (26/2).

The sets of 2 different letters and duplicate either one of the letters 4 times - 2 options; or duplicate one letter 2 times, and the other 3 times - again 2 options. In total this is  = 4*(26/2).

The word has just 1 distinct letter you have =  (26/1).

we get :

N = (26/5)+ 4*(26/4) + 6*(26/3) + 4*(26/2) +  (26/1)

= 142506

The words need not be English language words  = 142506

Learn more about  permutation and combination

brainly.com/question/28065038

#SPJ4

5 0
1 year ago
On the first play during the football game our team gained 5 yards. Between both the second and third play our team lost eight y
Maurinko [17]

Answer:

loss

Step-by-step explanation:

you might want to check someone else answer first tho

7 0
3 years ago
If AD = 12 and BD = 14, what is CD?
tigry1 [53]

Answer: D. 16.33

Step-by-step explanation:

5 0
2 years ago
The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f
Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen  who carry a credit card balance.

The formula for the interval is:

p'₁±Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }

Z_{1-\alpha /2}= Z_{0.95}= 1.648

0.37±1.648*\sqrt{\frac{0.37*0.63}{1000} }

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂±Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }

0.48±1.648* \sqrt{\frac{0.48*0.52}{1000} }

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: \sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015

Seniors: \sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0
4 years ago
Other questions:
  • Tanikwa started a new exercise program using the indoor track. In her first workout she ran 8 laps for every 4 laps that she wal
    12·1 answer
  • What is the total cost of $206.88 with a 5.75% sales tax
    8·2 answers
  • Long division with decimals
    13·2 answers
  • For the function f(x) = 3(x - 1)2 + 2, identify the vertex, domain, and range. (2 points)
    12·1 answer
  • If the formula for the perimeter of a rectangle is p= 2l+2w then w can be expressed as​
    5·1 answer
  • Will give brainliest if correct.
    7·1 answer
  • Recently, the value of a house increased by 20.5%.
    5·1 answer
  • Pls find m<1 TYSM! **the answer is not 40**
    15·1 answer
  • Simplify √0.49<br><br><br><br> ............
    11·1 answer
  • In the figure below, S is between Q and T and R is the midpoint of QS. If QT= 16 and RS=5, find ST.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!