Answer:
The equation of line with given points is y - 4 = 3 ( x + 2 ) .
Step-by-step explanation:
Given as :
The points of line are ( 1 , 13 ) and ( - 2 , 4 )
The point slope intercept equation of line is
y - 
= m ( x - 
)
Where m is the slope of line
So , Slope , m = 
Or, m = 
Or, m = 
∴ m = 3
Now The equation of line is
y - = m ( x - )
Or. y - 13 = 3 ( x - 1 )
Or, y - 13 = 3 x - 3
Or, y = 3 x - 3 + 13
∴ y = 3 x + 10
I.e y - 4 = 3 x + 6
Or, y - 4 = 3 ( x + 2 )
Hence The equation of line with given points is y - 4 = 3 ( x + 2 ) . Answer
Answer:
Value of stamp collection = (45b + 43) cents
Step-by-step explanation:
What we have here is as follows;
if there are x 3-cent stamps, then there are 4x 10-cent stamps
So the number of 2-cent stamps is 1 less than 3 cent stamps and that will be x-1 2 cent stamps
Number of 2 cents stamps = b
This means that x-1 = b
Thus, x = b + 1
So the value of the stamp collection is as follows;
x 3 cents stamps = 3(b+ 1) = 3b + 3 cents
4x 10 cents stamps = 10(4(b + 1)) = 10(4b + 4) = 40b + 40
value of the 2 cents stamp = 2b cents
Total value is thus;
2b + 40b + 40 + 3b + 3 = (45b + 43) cents
120:30 --> 4+1=5. 150/5=30. 30*4=120. 30*1=30 :) Hope this helped!
Just solve the quadratic, you need to figure out what value you can use to FOIL and get c^2+5c-24=0. so you need to figure out what values you can add together to get 5 and multiply together to get -24 so try (c+8)(c-3) here 8 and 3 make sense since 8-3 = 5 and 8*-3=-24 so the answer is (c+8)(c-3).
