URGENT PLEASE HELP Definitely need the correct answers as I am failing precalculus

Mathematics

1 answer:

dangina [55]3 years ago

6 0

Answer (first one):

${x|-2\leq x\leq 8}$

Step-by-step explanation:

think of f(x) as y.

$y>-2$

Now find the parts on the x axis that correspond with parts on the y value that are greater than -2.

$x\geq -2 \\x \leq 8$

This would be all of the numbers between -2 and 8 (inclusive).

The reason it is inclusive is because the arrow ends are shaded in.

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Lindsay buys 15 3/4 gallons of gasoline for $3.50 per gallon how much the whole tank cost

nydimaria [60]

Answer:

The whole tank cost $55.13

Step-by-step explanation:

All you have to do is multiply the fraction and cost, to ge thte total cost

15 3/4 also equals 15.75 (it will be easier to multiply two fractions)

now each gall of the 15.75 costs 3.50 so we multiply the number of gallons by the cost

15.75 x 3.50 = 55.125

but now we must round since there isnt .125 cents

55.13 is the cost

4 0

2 years ago

Read 2 more answers

3x^2 - 4x = -2<br> Solve

amid [387]

Answer:

$x = \bigg \{\frac{ 2 - \sqrt{2} \: i }{3}, \: \: \frac{ 2 + \sqrt{2} \: i }{3} \bigg \}$

Step-by-step explanation:

$3 {x}^{2} - 4x = - 2 \\ 3 {x}^{2} - 4x + 2 = 0 \\ equating \: it \: with \\ a {x}^{2} + bx + c = 0 \\ a = 3 \: \: b = - 4 \: \: c = 2 \\ {b}^{2} - 4ac \\ = {( - 4)}^{2} - 4 \times 3 \times 2 \\ = 16 - 24 \\ = - 8 \\ \ {b}^{2} - 4ac < 0 \\ \therefore \: given \: quadratic \: equation \: have \: \\ imaginary \: solutios. \\ \\ x = \frac{ - b \pm \sqrt{{b}^{2} - 4ac } }{2a} \\ = \frac{ - ( - 4) \pm \sqrt{ - 8} }{2 \times 3} \\ = \frac{ 4 \pm 2\sqrt{2} \: i }{2 \times 3} \\ = \frac{ 2 \pm \sqrt{2} \: i }{3} \\ \therefore \: x = \frac{ 2 - \sqrt{2} \: i }{3} \: or \: x = \frac{ 2 + \sqrt{2} \: i }{3} \: \\ \\ x = \bigg \{\frac{ 2 - \sqrt{2} \: i }{3}, \: \: \frac{ 2 + \sqrt{2} \: i }{3} \bigg \}$