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lubasha [3.4K]
3 years ago
7

Someone please help me!!!! I’ll make you brainlist

Mathematics
1 answer:
iren [92.7K]3 years ago
8 0

Answer:

Volume of Pipe is 226 ft³.

Step-by-step explanation:

Given:

Cylindrical Shape Pipe having

Height = 18 ft

Diameter = 4 ft

∴ Radius =\frac{Diameter}{2}=\frac{4}{2}=2\ ft

To Find:

Volume of Pipe = ?

Solution:

Formula for Volume of Cylinder is given by

\textrm{Volume of Cylinder}=\pi (Radius)^{2} \times Height

Substituting the given values we get

\textrm{Volume of Pipe}=3.14\times 2^{2} \times 18\\\\\textrm{Volume of Pipe}=226.08\\\\\therefore \textrm{Volume of Pipe}=226\ ft^{3}

Volume of Pipe is 226 ft³.

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D) 5X-3 X 32x – 8 = 225​
aleksley [76]
The answer for this question is 100
7 0
3 years ago
Pls help ima give BRAINLIST and a like
Hoochie [10]

Answer:

the letter in the green box should be 3.

i believe the full equation should be y= -3/2 x+1

Step-by-step explanation:

the y side keeps decreasing by 1 1/2 which in improper fraction form is -3/2. the x side keeps increasing by 1.

7 0
3 years ago
A student who is trying to write a paper for a course has a choice of two topics, A and B. If topic A is chosen, the student wil
algol13

Answer:

P(Topic A) = 0.91

P(Topic B) = 0.9163

The student should choose Topic B to maximize the probability of writing a good paper because P(Topic B)>P(Topic A).

Step-by-step explanation:

If Topic A is chosen, 2 books will be ordered (n=2)

If topic B is chosen, 4 books will be ordered (n=4)

Probability that a book arrives in time (p) = 0.7

Probability that a book does not arrive in time (q) = 1 - p = 1 - 0.7 = 0.3

We will <u>use the binomial distribution</u> to find out which topic should the student choose to maximize the probability of writing a good paper. The binomial distribution formula is:

P(X=x) = ⁿCˣ pˣ qⁿ⁻ˣ

where p = probability of success

           q = probability of failure

           n = total no. of trials

           x = no. of successful trials

For Topic A, n = 2, p=0.7 and q=0.3. If topic A is chosen, the student will use at least half the books i.e. he will use either 1 or 2 books. So,

P(Topic A) = P(X=1) + P(X=2)

                 =²C₁ (0.7)¹(0.3)²⁻¹ + ²C₂ (0.7)²(0.3)²⁻²

                 = 0.42 + 0.49

P(Topic A) = 0.91

For topic B, n=4, p=0.7 and q=0.3. If topic B is chosen, the student will choose 2 or more books i.e. 2, 3 or 4 books.

P(Topic B) = P(X=2) + P(X=3) + P(X=4)

                  = ⁴C₂ (0.7)²(0.3)⁴⁻² + ⁴C₃ (0.7)³(0.3)⁴⁻³ + ⁴C₄ (0.7)⁴(0.3)⁴⁻⁴

                  = 0.2646 + 0.4116 + 0.2401

P(Topic B) = 0.9163

The student should choose Topic B to maximize the probability of writing a good paper because P(Topic B)>P(Topic A) as calculated above.

3 0
3 years ago
What percent is the change in the price if: a The price was $100 and now it is $1250?
KatRina [158]

Answer:

The increase is 1150.

11.5 times the original value, or 1150% of it. That's a big increase, and I would not buy that thing, whatever it is.

8 0
3 years ago
If you are reading this please help!!!!
Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

                          =-12 x^{5}+21 x^{2}

2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

                              =12 x^2+8x-15

3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

3 0
3 years ago
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