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Afina-wow [57]
3 years ago
5

A rectangular room has a length 8m and breadth 4m.find area of the room

Mathematics
2 answers:
timurjin [86]3 years ago
5 0

Answer: The area is 32

Step-by-step explanation: To find the area of a rectangle use this formula A=wl with A representing the area w representing the width and l representing the length.

AleksandrR [38]3 years ago
3 0

Answer:

8x4=32

Step-by-step explanation:

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Rachel multiplied each side of x ≥ 2 by 3. She wrote the result as 3x ≤ 6. Explain the error Rachel made.
andrey2020 [161]

Answer:

Her mistake was to change the inequality sign from ≥ to ≤.

The sign only changes when you multiply or divide both sides of an inequality by a negative number.

6 0
2 years ago
Can anybody help me???
marysya [2.9K]

Answer:

Help you with what? their is nothing!

6 0
3 years ago
Read 2 more answers
Can anyone answer this question with showing work <br> 532.6 • 8.53
MAVERICK [17]

The answer is: 4543.078

7 0
3 years ago
Squareroot(y-1) + 3 = y
jek_recluse [69]
Note:xy means x times y and x(y) means the same thing

so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0



squareroot(y-1)+3=y

isolate the squareroot
subtrac 3 from boht sides

squareroot(y-1)=y-3

square both sides (since they are equal, you should be able to square both sides and still make it true)

(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5

0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0

therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work



let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true

y=5
7 0
3 years ago
What is the length of QR?
Elena L [17]

Answer:

C

Step-by-step explanation:

Since the triangle is right with hypotenuse QR

Use Pythagoras' identity to solve for QR

The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is

QR² = 8² + (8\sqrt{3} )²

       = 64 + 192

       = 256 ( take the square root of both sides )

QR = \sqrt{256} = 16

7 0
3 years ago
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