All categories

3 years ago

In 2/5 hour, Matt can type 4/5 page. What is Matt's rate in pages per hour?

Mathematics

2 answers:

Fed [463]3 years ago

6 0

4/5 / 2/5
= 4/5 * 5/2
= 4/2
= 2

Answer: 2 pages per hour

Schach [20]3 years ago

6 0

It take him 24 minutes to type 4/5s of a page

You might be interested in

I NEED HELP ASAP ! PLS!

amm1812

Answer:

x = 106°

Step-by-step explanation:

sum of interior opposite angles of a triangular is equal to a exterior angle

= x +22= 40 +88

= x = 128- 22

x = 106 °

hope this answers will be helpful for you and plzzz mark my answer as brainlist plzzzz vote me also.....

5 0

2 years ago

Read 2 more answers

You are taking an exam and there are still many questions left to be solved. You already got 18 questions correct out of 25. The

UkoKoshka [18]

The answer is 2

Step-by-step explanation: 100% is the highest score you can have . then you have to divide 25 by 100 because 25 is the total amount of questions ,you should get 4,wich means each question is worth 4 points.

18 correct is a score of 72

20 correct is a score of 80

4x2=8 wich you need 8 more to get to 80 from 72

feel free to ask for more help :)

8 0

3 years ago

Find the sum of 4x ^ 2 - 7 and 6x ^ 2 - 5 .

almond37 [142]

Answer:

10x² - 12

Step-by-step explanation:

4x² - 7 + 6x² - 5 (combine like terms)

10x² - 12

3 0

3 years ago

Read 2 more answers

Find mFE<br> A) 52°<br> C) 76°<br> B) 93°<br> D) 112°

mixer [17]

Answer:

76 degrees

Step-by-step explanation:

GE = 180 since it is a straight line

GE = GR + FE

180 = 7x+6 +6x-8

Combine like terms

180 = 13x-2

Add 2 to each side

182 = 13x

Divide by 13

182/13 = 13x/13

14 =x

We want FE

FE = 6x-8

FE = 6(14) -8

=84 -8

=76

3 0

3 years ago

A torus is formed by rotating a circle of radius r about a line in the plane of the circle that is a distance R (> r) from th

jeyben [28]

Consider a circle with radius $r$ centered at some point $(R+r,0)$ on the $x$ -axis. This circle has equation

$(x-(R+r))^2+y^2=r^2$

Revolve the region bounded by this circle across the $y$ -axis to get a torus. Using the shell method, the volume of the resulting torus is

$\displaystyle2\pi\int_R^{R+2r}2xy\,\mathrm dx$

where $2y=\sqrt{r^2-(x-(R+r))^2}-(-\sqrt{r^2-(x-(R+r))^2})=2\sqrt{r^2-(x-(R+r))^2}$ .

So the volume is

$\displaystyle4\pi\int_R^{R+2r}x\sqrt{r^2-(x-(R+r))^2}\,\mathrm dx$

Substitute

$x-(R+r)=r\sin t\implies\mathrm dx=r\cos t\,\mathrm dt$

and the integral becomes

$\displaystyle4\pi r^2\int_{-\pi/2}^{\pi/2}(R+r+r\sin t)\cos^2t\,\mathrm dt$

Notice that $\sin t\cos^2t$ is an odd function, so the integral over $\left[-\frac\pi2,\frac\pi2\right]$ is 0. This leaves us with

$\displaystyle4\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}\cos^2t\,\mathrm dt$

Write

$\cos^2t=\dfrac{1+\cos(2t)}2$

so the volume is

$\displaystyle2\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}(1+\cos(2t))\,\mathrm dt=\boxed{2\pi^2r^2(R+r)}$

6 0

3 years ago