Given:
∠PRS and ∠VUW are supplementary.
To prove:
Line TV || Line QS
Solution:
Step 1: Given
∠PRS and ∠VUW are supplementary.
Step 2: By the definition of supplementary angles
![m\angle {PRS}+m\angle {VUW}=180^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20%7BPRS%7D%2Bm%5Cangle%20%7BVUW%7D%3D180%5E%7B%5Ccirc%7D)
Step 3: Angles forming a linear pair sum to 180°
![m\angle {PRS}+m\angle {SRU}=180^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%20%7BPRS%7D%2Bm%5Cangle%20%7BSRU%7D%3D180%5E%7B%5Ccirc%7D)
Step 4: By transitive property of equality
step 2 = step 3
![m\angle {PRS}+m\angle {VUW}=m\angle {PRS}+m\angle {SRU}](https://tex.z-dn.net/?f=m%5Cangle%20%7BPRS%7D%2Bm%5Cangle%20%7BVUW%7D%3Dm%5Cangle%20%7BPRS%7D%2Bm%5Cangle%20%7BSRU%7D)
Step 5: By algebra cancel the common terms in both side.
![{m} \angle {VUW}={m} \angle{SRU}](https://tex.z-dn.net/?f=%7Bm%7D%20%5Cangle%20%7BVUW%7D%3D%7Bm%7D%20%5Cangle%7BSRU%7D)
Step 6: By converse of corresponding angles postulate
Line TV || Line QS
Hence proved.
Answer:
Sorry nakalimutan ko
Step-by-step explanation:
Di koma search
Answer:
4 and 9 hundreths
Step-by-step explanation:
P(red) 4/9 on the first pull, P(red) 3/8 on the second pull
(4/9)(3/8) = 12/72 = 1/6 Letter D
Answer:
26 2/3 mph
Step-by-step explanation:
time = distance/speed
speed = distance/time
Use the first of these relations to find Aidan's time getting to school:
time = 16 mi/(40 mi/h) = 16/40 h = 0.4 h
Then the time Aidan takes to get home is 0.6 hours, and his average speed for that trip home is ...
speed = 16 mi/(0.6 h) = 26 2/3 mi/h