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Mrrafil [7]
3 years ago
8

What expression represents six times a number plus 8 times a number

Mathematics
1 answer:
zheka24 [161]3 years ago
4 0
6n + 8n

Which is 6 * n + 6 * 8, n being a number. 

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Match the right side of the equation to the left side<br> cot x sec^4 x=cot x+ 2 tan x+tan^3 x
Natalka [10]

Step-by-step explanation:

cot x + 2 tan x + tan³ x

Write in terms of sine and cosine:

(cos x / sin x) + 2 (sin x / cos x) + (sin³ x / cos³ x)

Find the common denominator:

(cos⁴ x / (sin x cos³ x) + 2 (sin² x cos² x / (sin x cos³ x)) + (sin⁴ x / (sin x cos³ x))

Add:

(cos⁴ x + 2 sin² x cos² x + sin⁴ x) / (sin x cos³ x)

Factor:

(sin² x + cos² x)² / (sin x cos³ x)

Pythagorean identity:

1 / (sin x cos³ x)

Multiply top and bottom by cos x:

cos x / (sin x cos⁴ x)

Simplify:

cot x sec⁴ x

5 0
3 years ago
9/x+7 = 4<br> i need the answer for my homework, please help x
Pachacha [2.7K]
Your answer is Answer:
x = -3
4 0
3 years ago
HELP PLEASE‼️‼️‼️ DUE TODAY ANSWER QUESTIONS 8-19 SHOW WORKKKKKK
Alecsey [184]

Answer:

in which class are

Step-by-step explanation:

tell in in this number 9684574163

3 0
3 years ago
Give me a correct answer, My answer probably wrong.
Georgia [21]

Hello!

This is a problem about the general solution of a differential equation.

What we can first do here is separate the variables so that we have the same variable for each side (ex. dy with the y term and dx with the x term).

\frac{dy}{dx}=\frac{x-1}{3y^2}

3y^2dy=x-1dx

Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.

y^3=\frac{1}{2}x^2-x+C

Then here, we just solve for y and we have our general solution.

y=\sqrt[3]{\frac{1}{2}x^2-x+C}

We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.

Hope this helps!

3 0
2 years ago
Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y
Lilit [14]
No he's not correct

<span>(3 – 6y2)(y2 + 2)  
= 3(y2) -6(y2)(y2)  - 6y2(2) </span>+ 3(2)<span>
= 3y2 -6y4 - 12y2 </span>+ 6 <span>
= -6y4 - 9y2 +6</span>
3 0
3 years ago
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