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vovikov84 [41]
4 years ago
12

A cube has a volume of 216 cubic inches. What is the length of each edge of the cube?

Mathematics
2 answers:
prisoha [69]4 years ago
7 0

Answer:

\boxed {\tt 6 \ centimeters}

Step-by-step explanation:

The volume of a cube can be found using the following formula:

v=s^3

where s is the side length, or edge.

We know the volume is 216 cubic inches. We can substitute 216 cm³ in for v, the volume.

216 \ cm^3 = s^3

We want to find the side length. Therefore, we must isolate the variable, s.

s is being cubed. The inverse of a cube is the cube root. Take the cube root of both sides of the equation.

\sqrt[3]{216 \ cm^3} =\sqrt[3]{s^3}

\sqrt[3]{216 \ cm^3} =s

6 \ cm=s

The length of each edge of the cube is 6 centimeters.

KatRina [158]4 years ago
3 0

Volume of a cube = (edge)^3

In this problem,

Volume = 216in^2

Edge = ?

Let's plug our values into the formula above.

216in^3 = (edge)^3

Take the cbrt of both sides.

6in = edge

The length of each edge = 6in

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6) \frac{x+7}{x^{2}+4\cdot x - 21} is equivalent to \frac{1}{x-3} for all x \ne 3. (Answer: None)

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Step-by-step explanation:

We proceed to simplify each expression below:

4) \frac{x}{7\cdot x +x^{2}}

(i) \frac{x}{7\cdot x +x^{2}} Given

(ii) \frac{x}{x\cdot (7+x)} Distributive property

(iii) \frac{1}{7+x} \cdot \frac{x}{x} Distributive property

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Rational functions are undefined when denominator equals 0. That is:

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Hence, we conclude that \frac{x}{7\cdot x +x^{2}} is equivalent to \frac{1}{7+x} for all x \ne -7. (Answer: A)

5) \frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}

(i) \frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}} Given

(ii) \frac{x^{3}\cdot (-14)}{x^{3}\cdot (1-5\cdot x)} Distributive property

(iii) \frac{x^{3}}{x^{3}} \cdot \left(-\frac{14}{1-5\cdot x} \right) Distributive property

(iv) -\frac{14}{1-5\cdot x} Commutative property/Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

1-5\cdot x = 0

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Hence, we conclude that \frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}} is equivalent to -\frac{14}{1-5\cdot x} for all x \ne \frac{1}{5}. (Answer: B)

6) \frac{x+7}{x^{2}+4\cdot x - 21}

(i) \frac{x+7}{x^{2}+4\cdot x - 21} Given

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(iv) \frac{1}{x-3} Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

x-3 = 0

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Hence, we conclude that \frac{x+7}{x^{2}+4\cdot x - 21} is equivalent to \frac{1}{x-3} for all x \ne 3. (Answer: None)

7) \frac{x^{2}+3\cdot x -4}{x+4}

(i) \frac{x^{2}+3\cdot x -4}{x+4} Given

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