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alex41 [277]
3 years ago
10

I'm uneducated and need help please..​

Mathematics
2 answers:
lapo4ka [179]3 years ago
7 0
The answer would have to be c
gogolik [260]3 years ago
6 0

Number one is c. It should take her about nine days

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Ella has 0.5 lbs of sugar. How much water should she add to make the following concentrations? Tell Ella how much syrup she will
HACTEHA [7]

Ella has to add 32.833 lbs of water to get 33.333 lbs of syrup.

<u>Solution:</u>

Ella has 0.5 lbs of sugar. Let x lbs be the amount of water Ella should add to get the 1.5% of syrup,

\Rightarrow0.5\text{ lbs }- 1.5\%

\Rightarrow x+0.5\text{ lbs }- 100\%

On writing the proportion,

\Rightarrow\dfrac{0.5}{x+0.5}=\dfrac{1.5}{100}\\ \\\Rightarrow0.5\cdot 100=(x+0.5)\cdot 1.5\\ \\\Rightarrow50=1.5x+0.75\\ \\\Rightarrow1.5x=50-0.75\\ \\\Rightarrow1.5x=49.25\\ \\\Rightarrow x=\dfrac{49.25}{1.5}\approx 32.833\ lbs

To get 1.5% syrup Ella should add 32.833 lbs of water. The total weight of syrup is 33.333 lbs.

7 0
3 years ago
Can someone help me on this it is so confusing to me. Will give Brainliest!
quester [9]

Answer:

Step-by-step explanation:

Janet uses less than 4 cups of flour because 3/8 is less than one.

4 0
2 years ago
Read 2 more answers
a cone is formed out of cement. The circumference of the base of the cone is 44 feet and the cone has a height of 6 feet. What i
aev [14]
The base is 44 cut that in half to get the radius, R=22 height=6 
fill in v=1/3 x 3.14 x r^2 x H
v = 1/3 x 3.14 x 22^2 x 6
22 x 22= 484
484 x 6 = 2904
2904 x 3.14= 9118.56
9118.56 x 1/3 = 9118.56/1 divided by 2735568/3 = 300
7 0
2 years ago
Read 2 more answers
Find the equation of the line that passes through points A and B<br> B (2, 3) and B(2,3)​
Anika [276]

Answer:

y = 2x - 1

Step-by-step explanation:

(4,7) (2,3)

slope = (7-3)/(4-2) = 4/2 = 2

y = 2x + c

when x=4 , y=7

7 = 2(4) + c

c = 7-8 = -1

y = 2x - 1

6 0
3 years ago
The logistic equation for the population​ (in thousands) of a certain species is given by:
Eva8 [605]

Answer:

a.

b. 1.5

c. 1.5

d. No

Step-by-step explanation:

a. First, let's solve the differential equation:

\frac{dp}{dt} =3p-2p^2

Divide both sides by 3p-2p^2  and multiply both sides by dt:

\frac{dp}{3p-2p^2}=dt

Integrate both sides:

\int\ \frac{1}{3p-2p^2}  dp =\int\ dt

Evaluate the integrals and simplify:

p(t)=\frac{3e^{3t} }{C_1+2e^{3t}}

Where C1 is an arbitrary constant

I sketched the direction field using a computer software. You can see it in the picture that I attached you.

b. First let's find the constant C1 for the initial condition given:

p(0)=3=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}

Solving for C1:

C_1=-1

Now, let's evaluate the limit:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-1 }  \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2-e^{-3x}  }

The expression -e^{-3x} tends to zero as x approaches ∞ . Hence:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-1 } =\frac{3}{2} =1.5

c. As we did before, let's find the constant C1 for the initial condition given:

p(0)=0.8=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}

Solving for C1:

C_1=1.75

Now, let's evaluate the limit:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}+1.75 }  \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2+1.75e^{-3x}  }

The expression -e^{-3x} tends to zero as x approaches ∞ . Hence:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}+1.75 } =\frac{3}{2} =1.5

d. To figure out that, we need to do the same procedure as we did before. So,  let's find the constant C1 for the initial condition given:

p(0)=2=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}

Solving for C1:

C_1=-\frac{1}{2} =-0.5

Can a population of 2000 ever decline to 800? well, let's find the limit of the function when it approaches to ∞:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-0.5 }  \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2-0.5e^{-3x}  }

The expression -e^{-3x} tends to zero as x approaches ∞ . Hence:

\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-0.5 } =\frac{3}{2} =1.5

Therefore, a population of 2000 never will decline to 800.

6 0
3 years ago
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