The sum of the first n natural numbers and 0=
n*(n+1)/2
True
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Answer: 1/12 of a cup
To get this answer, you multiply 1/4 by 1/3
Multiply straight across
(1/4)*(1/3) = (1*1)/(4*3) = 1/12
<h3>
Answer: 2p + 3q</h3>
Work Shown:
log(200) = log(2^3*5^2)
log(200) = log(2^3) + log(5^2)
log(200) = 3*log(2) + 2*log(5)
log(200) = 3*q + 2*p
log(200) = 2p + 3q
The log rules I used were
log(A*B) = log(A)+log(B)
log(A^B) = B*log(A)
