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alex41 [277]
4 years ago
10

I'm uneducated and need help please..​

Mathematics
2 answers:
lapo4ka [179]4 years ago
7 0
The answer would have to be c
gogolik [260]4 years ago
6 0

Number one is c. It should take her about nine days

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Let u = <-9,4>, v = <8, -5>. Find u - v.
OLEGan [10]
I am guessing vectors :)

(-17, 9)

or in polar form

√370, -27°53'50"
7 0
3 years ago
five percent of a batch of fuel was found faullty if 27 fuses were faulty how many were inspected the price of internet service
LenKa [72]

There are 540 fuses in total and the original price of the internet is $55.91

<h3>How to work with percentages?</h3>

a) We know that 5% of the fuses are faulty, and there are 27 faulty fusses, then we can write:

5% = 27

100% = x

We want to find x, to do that, we can write:

x = 27*(100%/5%) = 27*20 = 540

There are 540 fuses in total.

b) Now we know that the original price is P, and when we decrease it by 7%, then new price is $52.00

Then we can write:

$52.00 = P*(1 - 7%/100%)

$52.00 = P*(0.93)

$52.00/0.93 = P = $55.91

The original price is $55.91

If you want to learn more about percentages:

brainly.com/question/843074

#SPJ1

8 0
3 years ago
HELPPPP PLEASE!!!!!!!!!!!!
PtichkaEL [24]

Answer:

C

Step-by-step explanation:

7 - 2 = 5

11 - 3(2)

11 - 6 = 5

4(2) - 3

8 - 3 = 5

C is the only one that doesn't equal 5

5 0
3 years ago
The area of a circular lake is 16 km<br> 2
artcher [175]

Answer:

I can't fix stupid- sorry-

Step-by-step explanation:

3 0
3 years ago
A particle moves along line segments from the origin to the points (2, 0, 0), (2, 4, 1), (0, 4, 1), and back to the origin under
Shkiper50 [21]

The work is equal to the line integral of \vec F over each line segment.

Parameterize the paths

  • from (0, 0, 0) to (2, 0, 0) by \vec r_1(t)=t\,\vec\imath with 0\le t\le2,
  • from (2, 0, 0) to (2, 4, 1) by \vec r_2(t)=2\,\vec\imath+4t\,\vec\jmath+t\,\vec k with 0\le t\le1,
  • from (2, 4, 1) to (0, 4, 1) by \vec r_3(t)=(2-t)\,\vec\imath+4\,\vec\jmath+\vec k with 0\le t\le2, and
  • from (0, 4, 1) to (0, 0, 0) by \vec r_4(t)=(4-4t)\,\vec\jmath+(1-t)\,\vec k with 0\le t\le1

The work done by \vec F over each segment (call them C_1,\ldots,C_4) is

\displaystyle\int_{C_1}\vec F\cdot\mathrm d\vec r_1=\int_0^2\vec0\cdot\vec\imath\,\mathrm dt=0

\displaystyle\int_{C_2}\vec F\cdot\mathrm d\vec r_2=\int_0^1(t^2\,\vec\imath+24t\,\vec\jmath+32t^2\,\vec k)\cdot(4\,\vec\jmath+\vec k)\,\mathrm dt=\int_0^1(96t+32t^2)\,\mathrm dt=\frac{176}3

\displaystyle\int_{C_3}\vec F\cdot\mathrm d\vec r_3=\int_0^2(\vec\imath+(24-12t)\,\vec\jmath+32\,\vec k)\cdot(-\vec\imath)\,\mathrm dr=-\int_0^2\mathrm dt=-2

\displaystyle\int_{C_4}\vec F\cdot\mathrm d\vec r_4=\int_0^1((1-t)^2\,\vec\imath+2(4-4t)^2\,\vec k)\cdot(-4\,\vec\jmath-\vec k)\,\mathrm dt=-2\int_0^1(4-4t)^2\,\mathrm dt=-\frac{32}3

Then the total work done by \vec F over the particle's path is 46.

8 0
4 years ago
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