Answer:
x >8
Step-by-step explanation:
I think it is game engine developer or ui
Answer:
He would make $36 for 12 pounds of strawberries
He would make $196 for 49 pounds of blueberries
He would make 3S if he sold S pounds of strawberries
He would make 4B if he sold B pounds of blueberries
Working:
We know that strawberries are $3/pound so $3 x 12pounds = $36
We know that blueberries are $4/pound so $4 x 49pounds = $196
The letters represent the amount of pounds of fruit being bought so the calculation for that is ($ x pounds) so you would write this but without assigning a numerical value to the amount. So if the strawberries are $3/pound and Luke sold ‘s’ pounds then it would be 3S (or 3xS but that is already assumed). The same goes for the blueberries. We know that they are $4/pound so it would be 4B.
Sorry if this doesn’t make any sense but I hope this helped
Answer:
<em>The SUV is running at 70 km/h</em>
Step-by-step explanation:
<u>Speed As Rate Of Change
</u>
The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.
This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)
We'll compute :


We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

Thus we have

Solving for x'

Since y'=-60


The SUV is running at 70 km/h
Acute........................