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3 years ago

14

Need help with graph please asap, 12 points!

2 answers:

kolezko [41]3 years ago

8 0

For the green part
X (less than or equal to sign) y
The blue
Y(less than or equal to sign)6

Rus_ich [418]3 years ago

5 0

So since both these lines are solid lines and not dashed lines, the inequality is going to be either ≥ or ≤.

Starting with the horizontal line, all the points on that line have the y-coordinate of 6, therefore this line is going to be y_6. And since the shaded region is below the line, this inequality is going to be y ≤ 6.

With the next line, it is y_x. The y-intercept is (0,0) and the slope is 1. And since the shaded region is above this line, this inequality is going to be y ≥ x.

In short, the system of inequalities is y ≥ x and y ≤ 6.

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Solve the following inequality: ALGEBRA 1

hram777 [196]

Answer:

$m > 5$

Step-by-step explanation:

$\frac{m + 4}{3} > 3 \\ \frac{m + 4}{3} \times 3 > 3 \times 3 \\ m + 4 > 9 \\ m + 4 - 4 > 9 - 4 \\ m > 5$

3 0

2 years ago

I don’t get this I gotta find S(t)=

KiRa [710]

Answer:

multiply s by t

Step-by-step explanation:

you just multiply s times t and get your answer

5 0

3 years ago

Zanzabum

Answer :

Your are not clear in your question

5 0

3 years ago

Can someone help me find the slope

Serggg [28]

Answer:

I believe the answer is C, -4/5.

Step-by-step explanation:

You first find two points on the line and substitute them into the slope formula. I used points (-10,10) and (5,-2).

1. $y_2-y_1/x_2 - x_1$

2. -2-10/5-(-10)

3. -12/15

4. -4/5

I hope this helps, sorry for the late response.

6 0

3 years ago

In 1990, 23.8% of 18-24 year-olds in Biddeford, Maine were attending college. About 10 years later, a random sample of 610 18-24

Vlada [557]

Answer:

There is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 610

p = 23.8% = 0.238

Alpha, α = 0.01

Number of 18-24 year-old attending college , x = 178

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.238\\H_A: p > 0.238$

This is a one-tailed(right) test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{178}{610} = 0.2918$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.2918-0.238}{\sqrt{\frac{0.238(1-0.238)}{610}}} = 3.1201$

Now, we calculate the p-value from the table.

P-value = 0.0009

Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject the null hypothesis.

Conclusion:

Thus there is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

4 0

4 years ago

Read 2 more answers