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Brut [27]
3 years ago
11

Evaluate 9.5s +8.7t when s= 3 and t = 4

Mathematics
1 answer:
Arturiano [62]3 years ago
3 0
The answer is 63.3

9.5 * 3 + 8.7 * 4 = 63.3
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The perimeter of a square is 32 centimeters. What is the length of one side?
Lubov Fominskaja [6]
L= length of one side of the square
Ok so we know the perimeter is 32 cm. Perimeter is the sum of all the sides of a shape. Now all four sides of a square are the same length. That means 4*L=32.
Now that we have the equation 4*L=32, we need to find a number that when multiplied by four, equals 32. Since 4*8=32, we know the answer must be 8cm.
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Which of these graphs represents a function?
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The length of a rectangle is 3 meters greater than 2 times the width. The perimeter of the rectangle is 30 meters.What is the le
faust18 [17]

Answer:

11 meters

Step-by-step explanation:

Lets say that  w = width of the rectangle, to start. If the length of the rectangle is 3 meters greater than 2 times the width, the length of the rectangle is equal to 3 + 2w.  

The perimeter of the rectangle is 2 * length of rectangle + 2 * width of the rectangle. With the perimeter being equal to 30 and width being w and length being 2w+3:

The perimeter of the rectangle is 2(w) + 2(2w+3) = 30.  

We first need to find out w first, which will give us the width of the rectangle. Taking it step by step, we get:

2w + 4w + 6 = 30

6w + 6= 30

6w = 24 which is done by subtracting both sides by 6 to put the variables on one side and the values on the other side

w = 4 which is done by dividing 6 on both sides

Ultimately, this gets width to be 4 meters. Now that we found the width, we need to plug w = 4 into the equation we set up for length which is 2w+3.

That being said, the ANSWER is:

length of rectangle = 2(4)+3 = 11 meters

Hope this helps! :)

4 0
3 years ago
The lowa Hawkeyes recorded the following
Serga [27]

Answer:

-7, -2, 0, 5, 9, 12

Step-by-step explanation:

Negative numbers are obviously less that the positive, and well from there its fairly obvious

3 0
3 years ago
the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years​
Yuliya22 [10]

Answer:  125 g

<u>Step-by-step explanation:</u>

A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k

\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125

8 0
3 years ago
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