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alexandr1967 [171]
3 years ago
8

Find all possible values for each expression. sin^-1 1/2 a. 30° + 180n, 150° + 180n b. 30° + 360n, 150° + 360n c. 60° + 180n, 12

0° + 180n d. 60° + 360n, 120° + 360n
Mathematics
1 answer:
BartSMP [9]3 years ago
3 0

Answer:

Option B.

Step-by-step explanation:

The given expression is

\sin^{-1}\left(\dfrac{1}{2}\right)

It can be written as

\sin^{-1}\left(\dfrac{1}{2}\right)=\sin^{-1}\left(\sin (30^\circ\right)    [\because \sin (30^\circ)=\dfrac{1}{2}]

\sin^{-1}\left(\dfrac{1}{2}\right)=30^\circ

We know that sin is positive in first and second quadrant.

For first quadrant,

\theta=30^\circ

For second quadrant,

\pi-\theta =180-30=150^\circ

So, the required angles are 30^\circ+360n,150^\circ+360n.

Therefore, the correct option is B.

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The sides of a square are all increased by 3 cm. The area of the new square is 64 cm'.
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Side of the original square is 5 cm.

Step-by-step explanation:

  • Step 1: Let the side of the original square be x. Then side of the new square = x + 3 and Area of new square = 64 cm²

Area of a square = (side)²

⇒ 64 = (x + 3)²

⇒ 64 = x² + 6x + 9

⇒ x² + 6x - 55 = 0

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⇒ x(x + 11) - 5(x + 11) = 0

⇒ (x + 11)(x - 5) = 0

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3 years ago
WILL GIVE BRAINLIEST
Nat2105 [25]

May not be much help since I’m confused but if you want y or whatever, isolate the variable by doing the inverse operation.

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Ask yourself what is stopping the variable To be by itself?

And get rid of it bun doing the inverse operation

If you add, subtract

If you subtract, add

If you multiply, divide

If you divide, multiply

If your dealing with squared numbers, find the square root of it

If it’s sign isn’t there and it positive, subtract

If it’s sign isn’t there and it’s negative, add

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Step-by-step explanation:

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