Answer:
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The missing number is 23 because,
there is 3 feet in 1 yard
so, 7x3=21
21+2=23
so 7 yards and 2 feet = 23 feet
The value of sine theta = negative eight-seventeenths ⇒ 2nd
Step-by-step explanation:
Let us revise the quadrant of an angle its terminal side passes through a given point
- If the given point is (x , y), then the angle lies in the 1st quadrant
- If the given point is (-x , y), then the angle lies in the 2nd quadrant
- If the given point is (-x , -y), then the angle lies in the 3rd quadrant
- If the given point is (x , -y), then the angle lies in the 4th quadrant
∵ The terminal side of angle Ф passes through P (15 , -8)
∵ x = 15 and y = -8
- P is (x , -y), then the angle Ф lies in the 4th quadrant
∵ The terminal side of angle Ф is the hypotenuse of a right
triangle whose horizontal leg is 15 units and vertical leg
is -8 units
- Use Pythagoras Theorem to find the length of the hypotenuse
∴ Hypotenuse = 
units
∵ sinФ = 
∵ The side opposite to Ф is -8
∵ The hypotenuse is 17
∴ sinФ = 
The value of sine theta = negative eight-seventeenths
Learn more:
You can learn more about the trigonometry function in brainly.com/question/4924817
#LearnwithBrainly
1,2,9,4,12
hope this helps
a. Sean drank at a rate of 5 milliliters per second.
b. It took Sean 55 s to drink all the slushy.
<h3>a. How to find the rate at which Sean drank?</h3>
Since Sean darnak at a constant rate and originally there were 275 milliliters of slushy in the cup. After 13 seconds, 210 milliliters of slushy remained.
The rate at which Sean drank, r = Change in volume of slushy/time for change
= (275 mL - 210 mL)/13 s
= 65 mL/13 s
= 5 mL/s
So, Sean drank at a rate of 5 milliliters per second.
<h3>b. How long did it take Sean to drink all the slushy?</h3>
The time it takes Sean to drink all the slushy is given by
T = V/r where
- V = total volume of slushy = 275 milliliters and
- r = rate of drinking by Sean = 5 mL/s
So, T = V/r
= 275 mL/5 mL/s
= 55 s
So, it took Sean 55 s to drink all the slushy.
Learn more about rate here:
brainly.com/question/8728504
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