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Vlada [557]
3 years ago
11

6- 3x = 5x-10x + 10 Solve for x

Mathematics
2 answers:
lubasha [3.4K]3 years ago
5 0

Answer:

6_3x=5x-10x+10

6-3x=-5x+10

6-3x+5x=10

6+2x=10

2x=10-6

2x=4

x=4/2

x=2

luda_lava [24]3 years ago
4 0

Step-by-step explanation:

I've shown the process in the picture.

hope it helps

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Rewrite the rational exponent as a radical by extending the properties of integer exponents. 2 to the 3 over 4 power, all over 2
Zepler [3.9K]
We are asked in this problem to determine the simplified expression of the statement given. The rules that apply in exponential functions is that when an exponential term is raised to the power of an integer, the simplified term has a degree that is equal to the product of the integers involved. The operations involved should be applicable to terms with the same base number only.  In this problem, we thus write:

2^3/4 / 2^1/2 = 2^3/4 * 2^-1/2 = = 2^(3/4 - 1/2) = 2^ 1/4. hence the answer is 2^0.25 or simply equal to 1.1892 determined using a calculator.
6 0
3 years ago
Pls help me with this problem
Alchen [17]

Answer:

Angle A: 90

Angle B: 48

Angle C: 42

Side length A (Hypotinuse): 23.9

SIde length B (Opposite): 17.8

Side length C (Adjacent): 16

Step-by-step explanation:

https://www.calculator.net/triangle-calculator.html?vc=42&vx=&vy=&va=90&vz=16&vb=&angleunits=d&x=0&y=0

6 0
3 years ago
Find the greatest number that divides451, 328 and 673 leaving 1, 4 and 1,respectively as remainders.
Vesna [10]

You're looking for the largest number <em>x</em> such that

<em>x</em> ≡ 1 (mod 451)

<em>x</em> ≡ 4 (mod 328)

<em>x</em> ≡ 1 (mod 673)

Recall that

<em>x</em> ≡ <em>a</em> (mod <em>m</em>)

<em>x</em> ≡ <em>b</em> (mod <em>n</em>)

is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly

1 ≡ 4 (mod 41)

is not true.

So there is no such number.

4 0
3 years ago
The ratio of girls to boys in Mr. Smith's homeroom is 3:4. The ratio in Mr. Smith's homeroom to students in the whole 7th grade
Leno4ka [110]

3:4 = G:B

1:5 = Mr. Smith's class: 7th Grade

2:7= 7th: Middle school

12 girls = 3 units

1 unit = 12/3= 4

Boys = 4x4= 16

<em>Whole class = 28 students</em>

Class : Grade = 1:5     <em> 7 = number of units in  Mr. Smith's class</em>

28 = 1 unit

5 units= 28x5= 140 <em>There are 140 kids in the grade</em>

140 = 2 units

1 unit = 140/2= 70

70x7=490

<u><em>There are 490 students in the whole grade</em></u>



6 0
3 years ago
Kyle asked a random group of students what their favorite sport was. The results are below. Boys Girls Basketball 10 8 Football
Ronch [10]

Answer:

The probability that Kyle will pick a girl who likes football is 12.5%.

Step-by-step explanation:

The data provided is as follows:

                         Boys        Girls       Total

Basketball          10             8             18

 Football           25             7             32

  Soccer             9             19             28

 Baseball           18            22            40

   Total               62           56            118

Compute the probability that Kyle will pick a girl who likes football as follows:

P(F|G)=\frac{n(G\cap F)}{n(G)}

            =\frac{7}{56}\\\\=0.125\\\\=12.5\%

Thus, the probability that Kyle will pick a girl who likes football is 12.5%.

6 0
3 years ago
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