1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pantera1 [17]
3 years ago
14

What is the area of the shaded area?

Mathematics
2 answers:
denis-greek [22]3 years ago
7 0

First you want to find the area of the square, which would be 121. ( 11 x 11 )

Next you want to find the area of the circle, 78.54 ((pi)5^2)

Last, you want to subtract the area of the circle, from the area of the square that is shaded. Youre left with 42.46

Hope this helped

rodikova [14]3 years ago
3 0

Step-by-step explanation:

Area of shaded portion = Area of square - area of circle

Area = 11² - 22/7 × 5 × 5

Area = 42.43 cm²

You might be interested in
In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which
mario62 [17]

2 out of 50 were tagged.

Divide 2 by 50:

2/50 = 0.4 ( This is 4% of the fish were tagged).

Now divide the number of fish caught by the percentage that were tagged:

50 / 0.04 = 1250

The number of fish in the pond is C. 1250

6 0
3 years ago
Show both decimal places (5.06).
lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

<h3>How to find the cost of each call ?</h3>

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6)  \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9  \frac{1}{2} 2) = 1.66

Therefore,the cost of a 9 ½2-minute call is 1.66.

Learn more about problems on cost of call, refer:

brainly.com/question/16584226

#SPJ9

4 0
1 year ago
9/35x7/16x20/21 reduce to lowest terms. Convert the answers to mixed numbers where possible
8_murik_8 [283]
The answer is .107 by working left to right
5 0
3 years ago
Free point and brainlyest to whoever types hi first!
matrenka [14]

Answer:

hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The side length of a 45-45-90 triangle are in the ratio 1:1:square2. What is tan 45 degrees?
Salsk061 [2.6K]

Answer:

B

Step-by-step explanation:

Took the test

3 0
3 years ago
Other questions:
  • I need an answer to this geometry question.
    9·1 answer
  • Which is a perfect square between 100 and 144
    12·1 answer
  • You estimate 120 to deliver materials to a construction site.One company offers 1/3 of the cost that you estimated. How many wil
    12·1 answer
  • Solve the following system of equations:<br> y = 5/4x - 2<br> y = -1/4x + 19<br><br> x = ? and y = ?
    10·2 answers
  • Looking for a math tutor am in 7th
    9·2 answers
  • This is confusinggggg
    8·1 answer
  • What is the total when the product of 57 and .22 is added to 7 percent of 57
    5·1 answer
  • There is 0.3 kg of tin in a sword.
    10·1 answer
  • HELPPPPPP HELPPP!!!!!!!! ASAPPPP PLS AHHHHHHH
    11·1 answer
  • 4.<br> Which point on the number line<br> represents 0.3?
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!