All categories

3 years ago

You don’t have to explain it I just need the answer

Mathematics

1 answer:

ladessa [460]3 years ago

8 0

The correct answer is :H=-3 ............

You might be interested in

Can someone please help me ??

adelina 88 [10]

Answer:

Step-by-step explanation:

The values are not vectors so ST/SR should be 3

6 0

2 years ago

Nine tenths of the grade 9 class are in the gym. If these students are divided into three equal groups, what fraction of the cla

Dahasolnce [82]

Times by 3. Then divide the top backup by 3 to get 9/30. 9/30+9/30+9/30=27/30=9/10.

3 0

4 years ago

Expand. If necessary, combine like terms. (3 + 4x) (3 - 4x)

shepuryov [24]

(3 + 4x) (3 - 4x)

We know the algebraic identity: (a - b)(a + b) = a^2 + b^2. Therefore, we should square 3 and 4x.

= (3)^2 - (4x)^2
9 - 16x^2

Answer:

9 - 16x^2

Hope you could understand.

If you have any query, feel free to ask

5 0

2 years ago

Chris and Mikala each got a candy bar that were the same size. Chris cut his

bazaltina [42]

Answer:

Chris ate more of his candy bar

6 0

3 years ago

Evaluate the following

IRINA_888 [86]

(a) $[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

Answer:

$[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5*2.5 }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5}{1} ]^{2}$

*canceling 2.5 in numerator and denominator*

$= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925$

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) $[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3} ] ^{2}$

Answer:

$[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\$

*using $[x^{a}]^b = x^{ab}$ *

$= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}$

*Again, using $[x^{a}]^b = x^{ab}$ *

$= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} } \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1$

Property used: 'Power of a power'

We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

3 0

3 years ago