So uhh what is your question?
Answer:
The equation for the trend line would be y = -1/100x + 25
Step-by-step explanation:
In order to find the trend line, we first need to find the slope. To do so, we need to find two points on the line. The points we'll use are (0, 25) and (2500, 0). Next, we use the slope formula.
m(slope) = (y2 - y1)/(x2 - x1)
m = (0 - 25)/(2500 - 5)
m = -25/2500
m = -1/100
Now that we have this we can use the slope and the intercept in slope intercept form to model the trend line.
y = mx + b
y = -1/100x + 25
<h3>
Answer: log(2)</h3>
Explanation:
The rule to use here is log(x)-log(y) = log(x/y)
So,
log(6)-log(3) = log(6/3) = log(2)
73℅ of 58
= (73/100) × 58
= (73×58)/100
= 4234/100
= 42.34
