Which sign is NOT for a chemical change?

a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re

Blababa [14]

Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

Given : 59.4 g of $H_2SO_4$ in 100 g of solution

moles of $H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61$

Volume of solution = $\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.83g/ml}=54.6ml$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.61\times 1000}{54.6ml}=11.2M$

To calculate the volume of acid, we use the equation given by neutralisation reaction:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of stock acid which is $H_2SO_4$

$M_2\text{ and }V_2$ are the molarity and volume of dilute acid which is $H_2SO_4$

We are given:

$M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL$

Putting values in above equation, we get:

$11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL$

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

4 0

3 years ago

The internet is a local communication network that allows only certain computers to connect and exchange information True or fal

choli [55]

False, the internet branches throughout many countries connecting you to the rest of the world from home. Hope it helped!

6 0

3 years ago

If the starting volume of a hot air balloon is 55,500 m3and the initial temperature is 21 °C, what is the temperature inside the

Dmitry_Shevchenko [17]

Answer:

T₂ = 392 K

Explanation:

Given that,

Initial volume of the hot air balloon, V₁ = 55500 m³

Initial temperature, T₁ = 21°C = 294 K

Final volume, V₂ = 74000 m³

We need to find the final temperature inside the balloon. The relation between the temperature and volume is given by charles law i.e.

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Where

T₂ is the final temperature

So,

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{294\times 74000 }{55500 }\\\\T_2=392\ K$

So, the new temperature is 392 K.

8 0

2 years ago

In a chemical equation what name does the left side have

Pachacha [2.7K]

A chemical equation is a short hand expression of a chemical reaction. There aretwo<span> parts to a chemical equation. The reactants are the elements or compounds on the left side of the arrow (-->). The elements and compounds to the right of the arrow are the products.</span>

4 0

3 years ago

For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this

Salsk061 [2.6K]

The following are the steps to complete and balnce the equation for the given reaction

<u>Explanation:</u>

We are given, NO2– is oxidized to NO3– and Ag is reduced to Ag

NO2– + Ag+ -----> NO3– + Ag(s)

Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3 N = +5

O = -2 O = -2

Ag = +1 Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

NO2– -----> NO3–

Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

NO2– + H2O -----> NO3–

Ag+ -----> Ag(s)

Step 4) Balance the H by adding H+

NO2– + H2O -----> NO3– + 2H+

Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

NO2– + H2O -----> NO3– + 2H+ + 2e-

Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

NO2– + H2O -----> NO3– + 2H+ + 2e-

2 Ag+ + 2e------> 2 Ag(s)

3 0

3 years ago