Yes what the other person said can I plz get an thanks
        
             
        
        
        
If you start with 0.30 m Mn₂ , at 12.5 pH, free Mn₂ concentration be equal to 4.6 x 10⁻¹¹ m
Initial molarity of Mn₂ = 0.30 M
Final molarity of Mn₂ = 4.6 x 10⁻¹¹
pH = ?
Ksp [Mn(OH)₂] = 4.6 x 10⁻¹⁴ (standard value)
Write the ionic equation
     Mn(OH)₂   →    Mn⁺² + 2OH⁻
     [Mn⁺²] = 4.6 x 10⁻¹¹
We will calculate the concentration of OH⁻ by using Ksp expression
     Ksp = [Mn⁺²][OH-]² 
     [Mn⁺²][OH⁻]² = 4.6 x 10⁻¹⁴
     [OH⁻]² = 4.6 x 10⁻¹⁴ / 4.6 x 10⁻¹¹
     [OH⁻]² = 10⁻³
     [OH⁻] = (10⁻³)¹⁽²
     [OH⁻] = 0.0316 M
Calculate the pOH
     pOH = -log [OH⁻] 
     pOH =  -log [0.0316] 
     pOH = 1.5
Now calculate pH
    pH = 14 - pOH
    pH = 14 - 1.5
    pH = 12.5
You can also learn about molarity from the following question:
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Answer:
Volcanoes cool off the earth by emitting heat from its interior. They also add islands and for example, Hawaii was created / is made out of volcanoes. The deposits from volcanoes can also be used for building materials. Volcanic explosions have caused the atmosphere and oceans to form. Volcanic deposits also create land which is fertile. 
 
        
             
        
        
        
The balanced chemical equation for the standard formation reaction of liquid acetic acid is given as ,
 →
  → 
The reaction that form the products from their elements in their standard state is called formation of reaction .The acetic acid consist C , H , and O , So, determine their standard state . Carbon is graphite at 25°C and 1 atm , whereas hydrogen and oxygen are diatomic gases . Hence , we start with unbalanced reaction.
 →
 → 
The balanced chemical equation for the standard formation reaction of liquid acetic acid as,
 →
  → 
The combustion of liquid acetic acid is given as,
 →
 →  ΔH =-873
                    ΔH =-873
learn more about  balancing chemical equation
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Answer:
6.67 M
Explanation:
Molarity = 
<em>Convert 200g NaOH to moles. Convert 750 mL to L.</em>
200 g NaOH x (1 mol/39.998 g) = 5.00025... mol NaOH
750 mL x (1 L/1000 mL) = 0.750 L
<em>Substitute values into the equation.</em>
Molarity = 
Molarity = 6.667... M
Molarity = 6.67 M