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3 years ago

What is the role of our company compliance Department

1 answer:

6 0

<h3>A compliance department identifies risks that an organization faces and advises on how to avoid or address them.It implements controls to protect the organization from those risks.</h3>

Hope This Answer Helps.

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A chemist fills a reaction vessel with mercurous chloride solid, mercury (I) aqueous solution, and chloride aqueous solution at

makvit [3.9K]

Answer:

ΔG° = -533.64 kJ

Explanation:

Let's consider the following reaction.

Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)

The standard Gibbs free energy (ΔG°) can be calculated using the following expression:

ΔG° = ∑np × ΔG°f(products) - ∑nr × ΔG°f(reactants)

where,

ni are the moles of reactants and products

ΔG°f(i) are the standard Gibbs free energies of formation of reactants and products

ΔG° = 1 mol × ΔG°f(Hg₂²⁺) + 2 mol × ΔG°f(Cl⁻) - 1 mol × ΔG°f(Hg₂Cl₂)

ΔG° = 1 mol × 148.85 kJ/mol + 2 mol × (-182.43 kJ/mol) - 1 mol × (-317.63 kJ/mol)

ΔG° = -533.64 kJ

3 0

3 years ago

What elements are found in salt?

devlian [24]

Sodium is a member of the alkali metal family with potassium (K) and Lithium (LI) sodium's big claim to fame is that it's one or two elements in your table salt. when bonded to chlorine (CI) THE two elements make sodium chloride

8 0

3 years ago

what volume of a 0.155 M calcium hydroxide solution is required to neutralize 28.8 mL of a 0.106 M nitric acid?

Hitman42 [59]

Answer:

9.85mL

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

Ca(OH)2 + 2HNO3 —> Ca(NO3)2 + 2H2O

From the balanced equation above,

nA (mole of the acid) = 2

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) =?

Mb (Molarity of base) = 0.155 M

Va (volume of the acid) = 28.8 mL

Ma (Molarity of acid) = 0.106 M

Using MaVa/MbVb = nA/nB, the volume of calcium hydroxide (i.e the base) can be obtain as follow:

MaVa/MbVb = nA/nB

0.106 x 28.8 / 0.155 x Vb = 2/1

Cross multiply to express in linear form as shown below:

2 x 0.155 x Vb = 0.106 x 28.8

Divide both side by 2 x 0.155

Vb = (0.106 x 28.8) / (2 x 0.155)

Vb = 9.85mL

Therefore, the Volume of calcium hydroxide is 9.85mL

7 0

3 years ago

Marina CMI [18]

Answer:

Molar mass = 30.026 g/mol

Explanation:

Let Molar mass be mm

mm of CH2O = 12.01 + 2(1.008) + 16.00

= 12.01 + 2.016 + 16.00 = 30.026 g/mol

6 0

2 years ago

The reaction between potassium chlorate and red phosphorus takes place when you strike a match on a matchbox. If you were to rea

mihalych1998 [28]

<u>Answer:</u> The mass of tetraphosphorus decaoxide formed is 64.81g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

<u>For potassium chlorate:</u>

Given mass of potassium chlorate = 93.3 g

Molar mass of potassium chlorate = 122.55 g/mol

Putting values in above equation, we get:

$\text{Moles of potassium chlorate}=\frac{93.3g}{122.55g/mol}=0.761mol$

For the given chemical reaction:

$10KClO_3+12P\rightarrow 3P_4O_{10}+10KCl$

Red phosphorus is given in excess . So, it is considered as an excess reagent and potassium chlorate is considered as a limiting reagent.

By Stoichiometry of the reaction:

10 moles of potassium chlorate reacts with 3 moles of tetraphosphorus decaoxide

So, 0.761 moles of potassium chlorate will react with = $\frac{3}{10}\times 0.761=0.2283moles$ of tetraphosphorus decaoxide

Calculating the mass of tetraphosphorus decaoxide by using equation 1, we get:

Molar mass of tetraphosphorus decaoxide = 283.886 g/mol

Moles of tetraphosphorus decaoxide = 0.2283 moles

Putting values in equation 1, we get:

$0.2283mol=\frac{\text{Mass of tetraphosphorus decaoxide}}{283.886g/mol}\\\\\text{Mass of tetraphosphorus decaoxide}=64.81g$

Hence, the mass of tetraphosphorus decaoxide formed is 64.81g

5 0

3 years ago