Why don't you try using the following kinematics formula
Vf^2 = Vi^2 + 2ad
Then solve for d, distance.
I'm guessing D. toothpick, but i might be wrong.
Momentum = (mass) x (velocity)
Original momentum before the hit =
(0.16 kg) x (38 m/s) this way <==
= 6.08 kg-m/s this way <==
Momentum after the hit =
(0.16) x (44 m/s) that way ==>
= 7.04 kg-m/s that way ==>
Change in momentum = (6.08 + 7.04) = 13.12 kg-m/s that way ==> .
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Change in momentum = impulse.
Impulse = (force) x (time the force lasted)
13.12 kg-m/s = (force) x (0.002 sec)
(13.12 kg-m/s) / (0.002 sec) = Force
6,560 kg-m/s² = 6,560 Newtons = Force
( about 1,475 pounds ! ! ! )
Answer:
The wavelength of the 320 Hz sound waves in the column of air is 1070 mm.
Explanation:
To solve the question, we note that the tube acts as a pipe with one end closed and that a stationary wave is formed in the tube from the top, to the bottom of the tube and back.
The simplest and the first wave form in the tube has length L = Lambda/4
That is, a node at the closed end and an antinode at the open end
The second stationary wave is given by
l + 535 mm= 3/4×lambda
However v = f×lambda
f = v/lambda = v/(4l)
Therefore
Lambda/4 + 535 mm = 3/4lambda
Or 535 mm = 3/4lambda -Lambda/4 = lambda/2
Therefore, lambda = 2×535 mm = 1070 mm
The wavelength = 1070 mm