By definition we have that the density is given by:
Where,
M: mass of the sample
V: volume occupied by the sample
Therefore, substituting values in the given equation we have:
Answer:
the density of a sample of gas with a mass of 30 g and a volume of 7500 cm3 is:
Answer:
The turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1.
Explanation:
Given:
The concentration of bovine carbonic anhydrase = total enzyme concentration = Et = 3.3 pmol⋅L^–1 = 3.3 × 10^–12 mol.L^–1
The maximum rate of reaction = Rmax (Vmax) = 222 μmol⋅L^–1⋅s^–1 = 222 × 10^–6 mol.L^–1⋅s^–1
The formula for the turnover number of an enzyme (kcat, or catalytic rate constant) = Rmax ÷ Et = 222 × 10^–6 mol.L^–1⋅s^–1 ÷ 3.3 × 10^–12 mol.L^–1 = 67,272,727.27 s^–1
Therefore, the turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1
Explanation:
Looking at the placement of primary colors in the RGB color wheel, the mixing of the red and green colors will create Yellow secondary color.
Answer:
c
Explanation:
electronic balance must always be at zero to prevent errors in measured value
