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mixer [17]
3 years ago
15

What will change the velocity of a periodic wave?

Physics
2 answers:
Travka [436]3 years ago
7 0

Changing the medium of the wave.

Waves is always determined by the properties of the medium, which means that changing the medium will change the velocity of the wave


GREYUIT [131]3 years ago
4 0

Answer:

Changing the medium of the wave.

Explanation:

Hi, a Periodic wave is a wave with a repeating continuous pattern or cycle that the source produces.

They are determined by the properties of the medium. So, if we change the medium of the wave It´s velocity will change.

The mediums are distinguished by their properties - the material they are made of and the physical properties of that material such as the density, the temperature, the elasticity, etc.  

Feel free to ask for more if needed or if you did not understand something.

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A) A spaceship passes you at a speed of 0.800c. You measure its length to be 31.2 m .How long would it be when at rest?
rosijanka [135]

Answer:

a

     l_o  =52 \  m

b

      l = 37.13 \ LY

Explanation:

From the question we are told that

    The  speed of the spaceship is  v  =  0.800c

    Here  c is the speed of light with value  c =  3.0*10^{8} \ m/s

    The  length is  l = 31.2 \  m

     The  distance of the star for earth is d = 145 \  light \  years

     The  speed is v_s = 2.90 *10^{8}

     

Generally the from the length contraction equation we have that

       l  =  l_o  \sqrt{1 -[\frac{v}{c } ]}

Now the when at rest the length is  l_o

So  

      l_o =\frac{l}{\sqrt{ 1 - \frac{v^2}{c^2 } } }

      l_o =\frac{ 31.2 }{ \sqrt{1 - \frac{(0.800c ) ^2}{c^2} } }

      l_o=52 \  m

Considering b  

  Applying above equation

            l  =l_o \sqrt{1 -  [\frac{v}{c } ]}

Here l_o  =145 \  LY(light \ years )

So

           l=145 *  \sqrt{1 -  \frac{v_s^2}{c^2 } }

            l =145 *  \sqrt{ 1 - \frac{2.9 *10^{8}}{3.0*10^{8}} }

            l = 37.13 \ LY

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