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hichkok12 [17]
3 years ago
15

An arrow is shot vertically upward at a rate of 250ft/s. Use the projectile formula h=−16t2+v0t to determine at what time(s), in

seconds, the arrow is at a height of 500ft. Round your answer(s) to the nearest tenth of a second.
Physics
2 answers:
shtirl [24]3 years ago
7 0

Answer:

2.4 sec and 13.3 sec

Explanation:

SIZIF [17.4K]3 years ago
6 0

Answer:

The arrow is at a height of 500 feet at time t = 2.35 seconds.

Explanation:

It is given that,

An arrow is shot vertically upward at a rate of 250 ft/s, v₀ = 250 ft/s

The projectile formula is given by :

h=-16t^2+v_ot

We need to find the time(s), in seconds, the arrow is at a height of 500 ft. So,

-16t^2+250t=500

On solving the above quadratic equation, we get the value of t as, t = 2.35 seconds

So, the arrow is at a height of 500 feet at time t = 2.35 seconds. Hence, this is the required solution.

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