Question

one of the solutions to x2 − 2x − 15 = 0 is x = −3. what is the other solution? x = −5 x = −1 x = 1 x = 5

Answer 1

$x^{2} -2x-15=0$
P(-15)
s(-2)
$x^{2} -5x+3x-15$
=x(x-5)+3(x-5)
=(x+3)(x-5)
x=5