The answer is: " 9a² + 7a " .
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Note: (3a)² + 7a = (3a)*(3a) + 7a = 9a² + 7a .
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100 ---> 96 is -4
96 ---> 104 is +8
104 ---> 88 is -16
88 ---> 120 is +32
120 ---> 56 is -64
So first we go down by 4, then up by 8, then down 16, then up 32, then finally down 64.
The pattern of numbers is: -4, +8, -16, +32, -64
Notice it's the powers of 2:
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64
each term doubles. Also each term alternates in sign. One is positive, then the next is negative and so on.
The last difference is -64, which doubles to -128. Change the sign to positive to get +128
Add 128 to the last term of 56 to get
128+56 = 184
Therefore, the final answer is 184
Answer:
See below.
Step-by-step explanation:
First, we can see that 
.
Thus, for the question, we can just plug -1 in:
Saying undefined (or unbounded) will be correct.
However, note that as x approaches 2, the values of y decrease in order to get to -1. In other words, 
will always be greater or equal to -1 (you can also see this from the graph). This means that as x approaches 2, f(x) will approach -.99 then -.999 then -.9999 until it reaches -1 and then go back up. What is important is that because of this, we can determine that:
This is because for the denominator, the +1 will always be greater than the f(x). This makes this increase towards positive infinity. Note that limits want the values of the function as it approaches it, not at it.
1. x - 16
2. x + 5
3. x divided by 48 (I don’t have the division symbol.)
Answer:
<u>Alternative hypothesis 1</u>: the mean amperage at which the fuses burn out is > 40 amperes.
<u>Alternative hypothesis 2</u>: the mean amperage at which the fuses burn out is < 40 amperes.
Step-by-step explanation:
Recall that the null hypothesis is the fact you want to refute and is in doubt.
So, in this specific case, <em>the null hypothesis would be that the mean amperage at which the fuses burn out is 40 amperes.
</em>
The alternative hypothesis are those that want to refute the null hypothesis, in this case there are 2:
<u>Alternative hypothesis 1:</u> the mean amperage at which the fuses burn out is > 40 amperes.
<u>Alternative hypothesis 2:</u> the mean amperage at which the fuses burn out is < 40 amperes.
