Question

Look at the image shown

Answer 1

Explanation:

It is known that an electron pair represents a domain. Hybridization of $BF_{3}$ will be calculated as follows.

       Hybridization = $\frac{1}{2}[\text{Valence electrons of central atom + no. of bonded atoms + negative charge - positive charge}]$

Valence electrons of boron are 3 and no. of bonded atoms in a $BF_{3}$ molecule is 3.

Therefore, calculate hybridization of $BF_{3}$ as follows.

          Hybridization = $\frac{1}{2}[\text{Valence electrons of central atom + no. of bonded atoms + negative charge - positive charge}]$

                              = $\frac{1}{2}[3 + 3 + 0]$

                               = 3

Hence, hybridization of $BF_{3}$ is $sp^{2}$, that is, trigonal planar.

Thus, we can conclude that the given image represents that it is a trigonal planar molecule with three domains.        

Answer 2

I believe it is the last answer, hope this helps!