4.79 x 10⁻⁷moldm⁻³
Explanation:
Given parameters:
pOH of RbOH = 6.32
Unknown:
Molarity of the base = ?
Solution:
The pH or pOH scale is used for expressing the level of acidity alkalinity of aqueous solutions.
pOH = -log[OH⁻]
we know the pOH to be 6.32
6.32 = -log[OH⁻]
[OH⁻] = inverse log₁₀(6.32)
[OH⁻] = 4.79 x 10⁻⁷moldm⁻³
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Answer:
Option c.
Explanation:
According to Newton's law, formula to solve this problem is:
F = m . a
Mass → 1000 kg
a → 3 m/s²
F = 1000 kg . 3m/s² → 3000 N
1 N = 1 kg . m/s² according to SI, Internation System of units.
Answer:
There are 6.022x10^23 molecules
<u>Answer:</u> The hydroxide ion concentration and pOH of the solution is and 2.88 respectively
<u>Explanation:</u>
We are given:
Concentration of barium hydroxide = 0.00066 M
The chemical equation for the dissociation of barium hydroxide follows:
1 mole of barium hydroxide produces 1 mole of barium ions and 2 moles of hydroxide ions
pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution
To calculate pOH of the solution, we use the equation:
We are given:
Putting values in above equation, we get:
Hence, the hydroxide ion concentration and pOH of the solution is and 2.88 respectively
<span>Decomposition reaction.</span>