C) the heat transfer to the boiler
First, we divide the number of atoms of silicon given in the problem above by Avogadro's number 6.6022 x10^23. This will give us the number of moles of silicon. Then, we multiply the number of moles by the molar mass of silicon.
number of moles = (3.6 x 10^20 atoms/6.022x10^23 atoms) = 5.97x10^-4 moles
Then, multiplying by the molar mass
(5.97x10^-4 moles)(28.0855 g/mol) = 0.017 grams
Answer:
acceleration (a)=8 m/s square.
Electrons are like that in a wire. If one moves they all have to move. Thus when you turn on a switch an electrical potential difference (created by a generator) immediately causes a force that tries to move the electrons.
Answer:
The percent isotopic abundance of Cu-65 is 30.79 %.
The percent isotopic abundance of Cu-63 is 69.21 %.
Explanation:
we know there are two naturally occurring isotopes of carbon, Cu-63 (62.9298 amu) and Cu-65 (64.9278 amu)
First of all we will set the fraction for both isotopes
X for the isotopes having mass 62.9298 amu
1-x for isotopes having mass 64.9278 amu
The average atomic mass of copper is 63.546 amu.
we will use the following equation,
62.9298 x + 64.9278 (1-x) = 63.546
62.9298x + 64.9278 - 64.9278x = 63.546
62.9298x - 64.9278x = 63.546 - 64.9278
-1.998 x = -1.3828
x=-1.3828 / -1.998
x= 0.6921
0.6921 × 100 = 69.21 %
69.21 % is abundance of Cu-63 because we solve the fraction x.
now we will calculate the abundance of Cu-65.
(1-x)
1-0.6921 = 0.3079
0.3079 × 100 = 30.79 %
30.79 % for Cu-65.
