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Bas_tet [7]
4 years ago
14

Suppose 10 and 6 are common factors of two numbers. What other factors must the numbers have in common? Explain.

Mathematics
2 answers:
Scorpion4ik [409]4 years ago
4 0

~hi

~hi

what you will need to do is find

numbers that are similar

example 6 times 10

and 10 times 6

~bie~

Lyrx [107]4 years ago
4 0
6 x 19 and 10x 6 p> bie
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Find the equation of the line that is perpendicular to y=5 through the point (-4,-6)
Nikolay [14]

Answer:

x=-4

Step-by-step explanation:

we know that

The given equation y=5 is a horizontal line (is parallel to the x-axis)

The slope of the given line is equal to zero

A perpendicular line to the given line is a vertical line (parallel to the y-axis)

so

The equation of a vertical line is equal to the x-coordinate of the point that passes through it

The point that passes through it is (-4,-6)

therefore

The equation of the perpendicular line is

x=-4

4 0
3 years ago
Sherman has 3 cats and 2 dogs. he wants to buy a toy for each of his pets. Sherman has 22$ to spend on pet toys. How much can he
WARRIOR [948]

Sherman wants to spend on each pet, so we are assuming he wants to spend the same amount. He has 5 pets in all (3 cats, 2 dogs)

Divide 22 with 5

22/5 = 4.4

He can spend $4.40, or in fraction form:

4 4/10 (Mixed fraction)

hope this helps

6 0
3 years ago
I need to know the whole thing please help
aleksley [76]

Answer:

a) A student travelling to school on public transport: 15/52 or 0.231

b) A student walking to school: 16/52 or 0.308

c) A student not cycling to school: 43/52 or 0.827

Step-by-step explanation:

Total people = 52

Travel Method          Frequency

Public Transport           12

Car                                 15

Cycle                               9

Walk                                16

Find the relative frequency of.

The formula used will be: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

a) A student travelling to school on public transport:

Given Frequency: 12

Size of sample space: 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 12/52

Decimal = 0.231

b) A student walking to school

Given Frequency: 16

Size of sample space. 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 16/52

Decimal = 0.308

c) A student not cycling to school.

We will consider all students except those who cycle.

12+15+16 = 43

Given Frequency: 43

Size of sample space. 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 43/52

Decimal = 0.827

6 0
3 years ago
I need help it's really hard<br>Properties of exponents
Agata [3.3K]

\bf 12^x\times 12^4=12^8\implies \stackrel{\textit{if the base is the same, so are the exponents}}{12^{x+4}=12^8} \\\\\\ x+4=8\implies x=4

3 0
3 years ago
Rebecca had these results when she drew 10 tiles from the bag. The bag has a total of 20 tiles. Her classmates got similar resul
7nadin3 [17]

Answer: 15 green 5 red

Step-by-step explanation:

if its less likely to pull red than green you would to chose the lowest amount

8 0
3 years ago
Read 2 more answers
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