F(x) = -3(x + 2)(x - 5)^3 > 0
(x + 2)(x - 5) > 0
x + 2 > 0 or x - 5 < 0
x > -2 or x < 5
-2 < x < 5
Therefore, the stated interval is false.
1. Rationalise the denominator
(20+10i+10i-5)/2^2-i^2
2. Collect like terms
((20-5)+(10i+10i))/2^2-i^2
3. Simplify (20-5)+(10i+10i) to 15+20i
15+20i/2^2-i^2
4. Simplify 2^2 to 4
15+20i/4-i^2
5. Use square rule
15+20i/4-(-1)
6. Simplify brackets
15+20i/4+1
7. Simplify 4+1 to 4
15+20i/5
8. Factor out the common term 5
5(2+4i)/5
9. Cancel 5
3+4i
10. Your final answer
3+4i
Have a nice day ;D
Answer: in the 4th quadrant
Step-by-step explanation:
it needs to be in y=mx+b (slope form) so it would be
- -y=-1/2x+2
- then divide everything by -1
- which is y=1/2 -2
- b=-2 m=1/2
- if you were to graph it, the line would be in the 4th quadrant
Each bus actually had 54 students. You take away the 7 kids who went in a car from the 331 since they didn’t go on a bus. Then, you divide that number, 324, with the 6 buses. So 324/6, which is 54. 54 kids in each bus. Hoped that helped! :)
Distribute invisible 1
9c+8+3c
move c's together
9c+3c+8
add
12c+8
tada