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3 years ago

What is the length of a rectangle with width 12 inches and an area of 66 inches^2

Mathematics

2 answers:

sammy [17]3 years ago

8 0

Answer:

The length is 5.5 inches

Step-by-step explanation:

The area of a rectangle is

A = lw

66 = l * 12

Divide each side by 12

66/12 = l

5.5 = l

The length is 5.5 inches

ivolga24 [154]3 years ago

3 0

Answer:

5.5 inches

Step-by-step explanation:

Length times width is the area so

12*width =66

same as

66/12=5.5 inches

Ask more questions in the comments if you are still confused.

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The area of a rectangle is 28square miles. The length is 7 miles.

Masja [62]

Area=length times width
area=28
length=7

28=7 times width
divide both sides by 7
4=width

the width is 4 miles
and perimiter is 22mi

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3 years ago

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OleMash [197]

First to Answer

Answer:

The correct option is the third option. -2 1/4 / -2/3 = 3 3/8

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2 years ago

Charlie puts $50000 in a stock account, but it loses money at a rate of 20%

Alina [70]

Answer:

You dind't include the answer choices but it should look something like

$50000(.8)^t$

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3 years ago

two pumps of different sizes, working together, can empty a fuel tank in 3 hours. the larger pump can empty the tank in 4 hours

bonufazy [111]

Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
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3 years ago

Read 2 more answers

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e. $\mu=61$ and $\sigma=9$

To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and $34+3(9)$ .

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ . (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0

2 years ago