Simplify the following:
(a^4 + 4 b^4)/(a^2 - 2 a b + 2 b^2)
A common factor of a^4 + 4 b^4 and a^2 - 2 a b + 2 b^2 is a^2 - 2 a b + 2 b^2, so (a^4 + 4 b^4)/(a^2 - 2 a b + 2 b^2) = ((a^2 + 2 a b + 2 b^2) (a^2 - 2 a b + 2 b^2))/(a^2 - 2 a b + 2 b^2):((a^2 + 2 a b + 2 b^2) (a^2 - 2 a b + 2 b^2))/(a^2 - 2 a b + 2 b^2)
((a^2 + 2 a b + 2 b^2) (a^2 - 2 a b + 2 b^2))/(a^2 - 2 a b + 2 b^2) = (a^2 - 2 a b + 2 b^2)/(a^2 - 2 a b + 2 b^2)×(a^2 + 2 a b + 2 b^2) = a^2 + 2 a b + 2 b^2:
Answer: a^2 + 2 a b + 2 b^2
No
There is not a common factor
Rational # is not integer and rational number is an integer.... sometimes you have to look close to what you read because that might give you the answer
Answer:
AB ≈ 9.11
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan44° = = = ( multiply both sides by AB )
AB × tan44° = 8.8 ( divide both sides by tan44° )
AB = ≈ 9.11 ( to 3 sf )