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2 years ago

Hi! ❤️ , im looking for some help here. ill give brainliest if able to.

Mathematics

1 answer:

olchik [2.2K]2 years ago

5 0

Hello there! The solution of your question has been given below.

<h3>Solution:</h3>

${6}^{ - 2} \\ = ( \frac{1}{6} ) ^{2} \\ = \frac{ {1}^{2} }{ {6}^{2} } \\ = \frac{1}{36}$

<h3>Answer:</h3>

Option B.

$\frac{1}{36}$

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The right answer is
0.627

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2 years ago

The histogram shows the height, in feet, of Black Cherry Trees.

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Answer:

31 total trees

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3 years ago

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-18 = 5v+7 simplify your answer as much as possible what is the solve for v

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Answer:

v = - 5

Step-by-step explanation:

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3 years ago

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7 liters of gasoline between their 4 cars. How many liters of gasoline should each car get?

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1.75 liters for each car.

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3 years ago

Read 2 more answers

(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi

Drupady [299]

Answer:

a. $\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. $x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. $c = \dfrac{3}{8} \ g/L$

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx = (5·c - 5·c/3)×dt = 20/3·c = $6\frac{2}{3} \cdot c \cdot dt$

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. The amount of salt, x after t minutes is given by the relation

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

$dx = 6\frac{2}{3} \cdot c \cdot dt$

$x(t) = \int\limits \, dx = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt$

$x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

$x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10$

$6\frac{2}{3} \times c =\dfrac{25 \ grams }{10}$

$c =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} } = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200} \ g/L = \dfrac{3}{8} \ g/L$

$c = \dfrac{3}{8} \ g/L$

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2 years ago