Hey there hope this helps you out
Answer:
cannot be determined
Step-by-step explanation:
We do not know if any of the angles are equal and are only given two sides.
We cannot determine if the two triangles are similar
An= mth term.
an=a₁+(n-1)*d
a₁₂=41
a₁₅=140
a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d
a₁+11d=41 (1)
a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d
a₁+14d=140 (2)
With the equiations (1) and (2) build a system of equations
a₁+11d=41
a₁+14d=140
we solve it.
-(a₁+11d=41)
a₁+14d=140
--------------------
3d=99 ⇒d=99/3=33
a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322
an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n
an=-355+33n
To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
Answer: 7:35 a. M
Step-by-step explanation:
Given that:
Snooze on alarm = 5 minutes
Snooze on cellphone = 7 minutes
If both activates at 7:00 a. M
Time at which both will activate again ;
Obtain the Lowest Common Multiple of 5 and 7
_5 __|5 ___|7
_7__ |1 ___|7
____ |1 ___| 1
Lowest common multiple = (5 * 7) = 35
Hence, both alarms will sound together again after 35 minutes = 7:00a.m + 35 minutes = 7:35 A. M
Answer:
the third option is the correct
